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Jlenok [28]
3 years ago
5

NEED HELP ASAP! NO LINKS PLEASE, WILL REPORT.

Mathematics
1 answer:
Paladinen [302]3 years ago
3 0

Answer:

16

Step-by-step explanation:

27-11= rest of the length missing

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Help me please answer as quickly as possible
malfutka [58]

Answer:   B) (-x, y)

<u>Step-by-step explanation:</u>

If a coordinate is reflected across the y-axis, the y-coordinate stays the same but the x-coordinate changes signs.

Consider (1, 2) as the original point.  Now reflect it across the y-axis.  The new coordinate is (-1, 2). The y-coordinate stayed the same (2) but the x-coordinate changed signs (1 → -1).

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In 1999, 68% of households with TV’s subscribed to cable TV. If 8,000 more subscribers are added to the number of households wit
iren2701 [21]

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45962560

Step-by-step explanation:

6 0
3 years ago
Please help!!!!!! thank you
guajiro [1.7K]
I think the answer is letter C
7 0
3 years ago
Look at the relationship between a and b.
tensa zangetsu [6.8K]

Answer:

42 is the answer to life, the universe, and the amount of pizza i need. The 0 is the amount of braincells i have and the 6 is because I have 6 working teeth. The 9 is because it is almost 10

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Step-by-step explanation:

well its all up there i legit have no brain cells

3 0
3 years ago
prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample
Zolol [24]

Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = \frac{cos \ \theta}{sin \ \theta}

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ \frac{cos \ \theta}{sin \ \theta}

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

5 0
3 years ago
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