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3 years ago

Newton’s 2nd law, Why do objects of different masses fall at the same rate

Physics

2 answers:

Tcecarenko [31]3 years ago

5 0

Answer:

Hope that helps <3

Explanation:

the force's that objects feel may be different because they have different masses, but the acceleration on earth they experience is exactly the same

xenn [34]3 years ago

3 0

Objects of different masses fall at the same rate since they both start at the same time and the force of gravity accelerates them. Therefore they will both land at the same time due to air resistance.

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Find the net work W done on the particle by the external forces during the motion of the particle in terms of the initial and fi

steposvetlana [31]

Answer:

$W=K_f-K_i$

Explanation:

The work done on a particle by external forces is defined as:

$W=\int\limits^{r_f}_{r_i} {F\cdot dr} \,$

According to Newton's second law $F=ma$ . Thus:

$W=\int\limits^{r_f}_{r_i}{ma\cdot dr} \,\\$

Acceleration is defined as the derivative of the speed with respect to time:

$W=m\int\limits^{r_f}_{r_i}{\frac{dv}{dt}\cdot dr} \,\\\\W=m\int\limits^{r_f}_{r_i}{dv \cdot \frac{dr}{dt}} \,$

Speed is defined as the derivative of the position with respect to time:

$W=m\int\limits^{v_f}_{v_i} v \cdot dv \,$

Kinetic energy is defined as $K=\frac{mv^2}{2}$ :

$W=m\frac{v_f^2}{2}-m\frac{v_i^2}{2}\\W=K_f-K_i$

3 0

3 years ago

What is the lens equation?

Strike441 [17]

The lens equation gives d relation between focal length, object distance n image distance.

1/f = 1/v + 1/u

seldon

7 0

3 years ago

Read 2 more answers

What happens when the mass of an object is greter

Paul [167]

The acceleration goes up.

4 0

3 years ago

If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2

kaheart [24]

Answer:

$\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K$

So then the difference of temperature across the material would be $\Delta T = 375 K$

Explanation:

For this case we can use the Fourier Law of heat conduction given by the following equation:

$Q = -kA \frac{\Delta T}{\Delta x}$ (1)

Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 represent the cross sectional area

Q= 3KW represent the rate of heat transfer

$\Delta T$ is the temperature of difference that we want to find

$\Delta x=2.5 cm =0.025 m$ represent the thickness of the material

If we solve $\Delta T$ in absolute value from the equation (1) we got:

$\Delta T =\frac{Q \Delta x}{Ak}$

First we convert 3KW to W and we got:

$Q= 3 KW* \frac{1000W}{1 Kw}= 3000 W$

And we have everything to replace and we got:

$\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K$

So then the difference of temperature across the material would be $\Delta T = 375 K$

5 0

4 years ago

What is the pressure exerted by an elephant who weighs 2500N and whose feet cover an area of 7.5m2?

qaws [65]

Answer:

0.00339905404

Explanation:

kg: 0.00339905404

pascals: 333.333333

pounds: 0.0483459126

8 0

3 years ago