What happens when the mass of an object is greter

A cricket ball has mass 0.155 kg. If the velocity of a bowled ball has a magnitude of 35.0 m/s and the batted ball's velocity is

FinnZ [79.3K]

Answer:

Magnitude of change in momentum = 4.65 kg.m/s

Magnitude of impulse = 4.65 kg.m/s

Magnitude of the average force applied by the bat = 1550 N

Explanation:

Mass of the cricket ball, m = 0.155 kg

Initial velocity of the ball, u = 35.0 m/s

final velocity of the ball after hitting the bat, v = 65.0 m/s

Time of contact, t = 2.00 ms = 2.00 × 10⁻³ s

Now,

Magnitude of change in momentum = Final momentum - Initial momentum

or

Magnitude of change in momentum = ( m × v ) - ( m × u )

or

Magnitude of change in momentum = ( 0.155 × 65 ) - ( 0.155 × 35 )

or

Magnitude of change in momentum = 10.075 - 5.425 = 4.65 kg.m/s

Now, Magnitude of impulse = change in momentum

thus,

Magnitude of impulse = 4.65 kg.m/s

Now,

magnitude of the average force applied by the bat = $\frac{\textup{Impulse}}{\textup{Time}}$

or

magnitude of the average force applied by the bat = $\frac{\textup{4.65}}{\textup{3}\times\textup{10}^{-3}}$

or

Magnitude of the average force applied by the bat = 1550 N

6 0

4 years ago

An object, located 80.0 cm from a concave lens, forms an image 39.6 cm from the lens on the same side as the object. What is the

kramer

Answer:

-78.4 cm

Explanation:

We can solve the problem by using the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

p is the distance of the object from the lens

q is the distance of the image from the lens

f is the focal length

Here we have

p = 80.0 cm

q = -39.6 cm (negative, because the image is on the same side as the object , so it is a virtual image)

Substituting, we find f:

$\frac{1}{f}=\frac{1}{80.0 cm}+\frac{1}{-39.6 cm}=-0.0128 cm^{-1}$

$f=\frac{1}{0.0128 cm^{-1}}=-78.4 cm$

5 0

4 years ago

How many electrons are in an element with an atomic number of 20 and an atomic mass of 40? options: ANSWER FOR BRAINLIES

mafiozo [28]

Answer:

B

Explanation:

4 0

3 years ago

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The voltage leaving the secondary coil of a transformer is equal to 240 V. The secondary coil is wrapped 8 times around the core

Lina20 [59]

The initial voltage at the primary= 750 V

Explanation:

for a transformer

Es/ Ep= Ns/ Np

Es= secondary voltage= 240 V

Ep= primary voltage

Ns= number of turns in the secondary=8

Np= Number of turns in the primary=25

so 240/Ep=8/25

Ep=750 V

7 0

3 years ago

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Question 12 (10 points)

Leni [432]

Answer:

d jjh hhv g 7655 ijv 77_* uyfgj 3&88 huih

6 0

2 years ago