<h3>The first law of thermodynamics :</h3>
According to this law, some heat given to the system is used to change the internal energy while the rest is used in doing work by the system.
This relationship is mathematically represented as follows:
ΔQ = ΔU + W
where ΔQ is the heat given or lost, ΔU is the change in internal energy and W is the work done.
<h3>The second law of thermodynamics :</h3>
If a room is not tidied or cleaned, it invariably becomes more messy and disorderly with time.
When the room is cleaned its entropy decreases but the effort to clean it has resulted in an increase in entropy outside the room that exceeds the entropy lost.
<h3>
The Third law of thermodynamics :</h3>
The entropy of a pure crystalline substance (perfect order) at absolute zero temperature is zero. This statement holds true if the perfect crystal has only one state with minimum energy.
It would be around 19.9 or 20. To get this you use Avogadro's number, 6.022x10^23, and divide the amount of molecules by this number, getting your amount of moles.
Electric current is necessary to transmit , encode and analyse information
Answer:
-1.82 °C
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 33.9 g
- Mass of water (solvent): 578 g = 0.578 kg
- Freezing point depression constant for water (Kb): -1.82 °C/m
Step 2: Calculate the molality of the solution
We will use the following expression.
m = mass of solute / molar mass of solute × kg of solvent
m = 33.9 g / 58.44 g/mol × 0.578 kg
m = 1.00 m
Step 3: Calculate the freezing point depression (ΔT)
The freezing point depression is a colligative property that, for a non-dissociated solute, can be calculated using the following expression:
ΔT = Kb × m
ΔT = -1.82 °C/m × 1.00 m
ΔT = -1.82 °C
If 4 moles of P is used by 5 mole of O2
then....0.489 moles will be used by 5/4 × .489 = .611 moles of O2
so .611 moles
so if 4 moles of P is burnt , 1 mole of P4O10 is produced ....so for .489 moles...... .489/4=.122 moles !
so mass will be .122× 283.89 = 34.7 grams
so first ans is .611 moles and second is 34.7 grams !
if you have any problem regarding this , just comment !!!
