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True [87]
3 years ago
13

Sulfur dioxide and nitrogen dioxide are considered to

Chemistry
1 answer:
quester [9]3 years ago
8 0

a)CO is the main air pollutant (b) All pollutants are not wastes (c) Water is polluted by dissolved oxygen (d) Lichens are pollution indicatorsnation:

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What are the three rules of thermodynamics?​
allochka39001 [22]
<h3>The first law of thermodynamics :</h3>

According to this law, some heat given to the system is used to change the internal energy while the rest is used in doing work by the system.

This relationship is mathematically represented as follows:

ΔQ = ΔU + W

where ΔQ is the heat given or lost, ΔU is the change in internal energy and W is the work done.

<h3>The second law of thermodynamics :</h3>

If a room is not tidied or cleaned, it invariably becomes more messy and disorderly with time.

When the room is cleaned its entropy decreases but the effort to clean it has resulted in an increase in entropy outside the room that exceeds the entropy lost.

<h3>The Third law of thermodynamics :</h3>

The entropy of a pure crystalline substance (perfect order) at absolute zero temperature is zero. This statement holds true if the perfect crystal has only one state with minimum energy.

7 0
3 years ago
Read 2 more answers
How many moles are 1.2x1025 molecules of NO2?
Bas_tet [7]
It would be around 19.9 or 20. To get this you use Avogadro's number, 6.022x10^23, and divide the amount of molecules by this number, getting your amount of moles. 
5 0
3 years ago
Electronic devices use ____________ to encode, analyze, or transmit information.
Dmitrij [34]
Electric current is necessary to transmit , encode and analyse information
4 0
3 years ago
If 33.9g NaCl are mixed into water and the total mass is 578g, what is the CHANGE in freezing if Kb= - 1.82C/M (molal)? Assume N
steposvetlana [31]

Answer:

-1.82 °C

Explanation:

Step 1: Given data

  • Mass of NaCl (solute): 33.9 g
  • Mass of water (solvent): 578 g = 0.578 kg
  • Freezing point depression constant for water (Kb): -1.82 °C/m

Step 2: Calculate the molality of the solution

We will use the following expression.

m = mass of solute / molar mass of solute × kg of solvent

m = 33.9 g / 58.44 g/mol × 0.578 kg

m = 1.00 m

Step 3: Calculate the freezing point depression (ΔT)

The freezing point depression is a colligative property that, for a non-dissociated solute, can be calculated using the following expression:

ΔT = Kb × m

ΔT = -1.82 °C/m × 1.00 m

ΔT = -1.82 °C

3 0
3 years ago
4P+ 5O2 -&gt; P4O10
Ratling [72]
If 4 moles of P is used by 5 mole of O2
then....0.489 moles will be used by 5/4 × .489 = .611 moles of O2

so .611 moles

so if 4 moles of P is burnt , 1 mole of P4O10 is produced ....so for .489 moles...... .489/4=.122 moles !
so mass will be .122× 283.89 = 34.7 grams

so first ans is .611 moles and second is 34.7 grams !

if you have any problem regarding this , just comment !!!
4 0
3 years ago
Read 2 more answers
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