Moles of CaBr2 = 5/molar mass of CaBr2
= 5/199.886
= 0.025 moles.
Hope this helps!
Answer:
455.4 g
Explanation:
Data given:
no. of moles of (NH₄)₂SO₄= 3.45 mol
mass of (NH₄)₂SO₄ = ?
Solution
Formula will be used
no.of moles = mass in grams / molar mass
Rearrange the above equation for mass
mass in grams = no. of moles x molar mass . . . . . . . . (1)
molar mass of (NH₄)₂SO₄
molar mass of (NH₄)₂SO₄ = 2(14 + 4(1)) + 32 + 4(16)
molar mass of (NH₄)₂SO₄ = 2 (14 +4) + 32 + 64
molar mass of (NH₄)₂SO₄ = 2 (18) + 32 + 64
molar mass of (NH₄)₂SO₄ = 36 + 32 + 64 = 132 g/mol
Put values in equation 1
mass in grams = 3.45 mole x 132 g/mol
mass in grams = 455.4 g
So,
mass of (NH₄)₂SO₄ = 455.4 g
The number of atoms in 12 grams of the isotope carbon 12.
Answer:
0.497 moles/L
Explanation:
The reaction that takes place is:
- C₃H₆O₃ + NaOH → C₃H₅ONa + H₂O
First we c<u>alculate the moles of lactic acid in 0,821 g</u>, using its molar mass:
- 0,821 g ÷ 90 g/mol = 9,122x10⁻³mol lactic acid
<em>One mole of lactic acid reacts with one mole of sodium hydroxide</em> (it is a monoprotic acid), so in 18,34 mL of NaOH solution there are 9,122x10⁻³moles of NaOH:
- 18.34 mL ÷ 1000 = 0,01834 L
- 9,122x10⁻³mol ÷ 0,01834 L = 0.497 moles/L