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3 years ago

What are the three rules of thermodynamics?

Chemistry

2 answers:

allochka39001 [22]3 years ago

7 0

<h3>The first law of thermodynamics :</h3>

According to this law, some heat given to the system is used to change the internal energy while the rest is used in doing work by the system.

This relationship is mathematically represented as follows:

ΔQ = ΔU + W

where ΔQ is the heat given or lost, ΔU is the change in internal energy and W is the work done.

<h3>The second law of thermodynamics :</h3>

If a room is not tidied or cleaned, it invariably becomes more messy and disorderly with time.

When the room is cleaned its entropy decreases but the effort to clean it has resulted in an increase in entropy outside the room that exceeds the entropy lost.

<h3>The Third law of thermodynamics :</h3>

The entropy of a pure crystalline substance (perfect order) at absolute zero temperature is zero. This statement holds true if the perfect crystal has only one state with minimum energy.

AlexFokin [52]3 years ago

5 0

<h3>Three rules of thermodynamics are:</h3>

Energy can neither be created nor destroyed.
For a spontaneous process, the entropy of the universe increases.
A perfect crystal at zero kelvin has zero entropy.

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The reaction between ethylene and hydrogen bromide to form ethyl bromide is carried out in a continuous reactor. The product str

iren2701 [21]

Answer:

Explanation:

The first thing to do is to write out the chemical equation showing the reaction between the two chemical compounds.

C2H4 + HBr ------------------------> C2H5Br.

The chemical species/compounds reacted in the ratio of 1 : 1 : 1. That is one mole of C2H4 reacted with one mole of HBr to give one mole of C2H5Br.

So, we are given; C2H5Br = 58.7 mol%, HBr = 18.3 mol%. Thus, for C2H4, we have [ 100 - (58.7 + 18.3)] = 23 mol%. Therefore, the limiting reagent is HBr.

So, if we have 100 mol/s ;

C2H5Br = 100 × 0.587 = 58.7 mol/s, HBr = 100 × 0.183 = 18.3 mol/s and C2H4 = 100 × 0.23 = 23 mol/s.

Therefore, the total value of the flow rate in the feed = (HBr in feed) mol/s + (C2H4 in feed) mol/s = (58.7 + 18.3)mol/s + (58.7 + 23) mol/s =( 77 + 81.7) mol/s = 158.7 mol/s. .

So, 100/158.7 × 30.5 = 192.2.

Also the feed composition in HBr and C2H4 is;

HBr = 77/158.7 = 0.4852, C2H4 = 81.7/158.7 = 0.515.

Therefore, the number of HBr in feed and C2H4 in feed = 160m/s and 200m/s respectively (approx.)

Therefore, the fraction conversion is;

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3 years ago

Calculate the enthalpy change (in joules) involved in converting 5.00 grams of water at 14.0 °c to steam at 115 °c under a const

tensa zangetsu [6.8K]

Enthalpy change is the term given to the concentration of the heat absorbed or evolved in a reaction carried out at a constant pressure. It is given by the symbol ΔH.

Enthalpy change = m (Cwater × dT + Hvap + Csteam × dT

dHvap = 40.67 kJ/mol = 40.67 × 103/18 = 2259.4 J/g

Enthalpy change = 5.00 [4.18 × (100-14) + 2259.4 + 1.84 × (115-100)]

= 13232.4 J

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3 years ago

In a game of tug of war, team one pulls to the right with a force of 500 newtons and team two pulls to the left with a force of

SOVA2 [1]

Answer:

100 n to the right

Explanation:

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3 years ago

An unknown compound has a percent composition of 52.10% potassium, 15.8% carbon, and 32.1% oxygen. The molar mass of the compoun

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To determine the empirical formula and the molecular formula of the compound, we assume a basis of the compound of 100 g. We do as follows:

Mass Moles
K 52.10 52.10/39.10 = 1.33 1.33/1.32 ≈ 1
C 15.8 15.8/12 = 1.32 1.32/1.32 ≈ 1
O 32.1 32.1 / 16 = 2.01 2.01/1.32 ≈ 1.5

The empirical formula would most likely be KCO.
The molecular formula would be K2C2O3.

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4 years ago

Read 2 more answers

What is atomic mass?

vovikov84 [41]

Atomic mass is the quantity of protons that have in a atom. Which atom have different numbers of protons, being able to be identified by them.

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3 years ago

What are the three rules of thermodynamics?​

What are the three rules of thermodynamics?