
- From the first mechanism, it can be seen that the Aluminum is reduced at cathode and Florine is oxidized at anode.
- The ratio of aluminium and fluorine is the ratio of their change in oxidation number, i.e. 2:3
<em><u>༒</u></em><em><u>H</u></em><em><u>O</u></em><em><u>P</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>O</u></em><em><u> </u></em><em><u>I</u></em><em><u>T</u></em><em><u> </u></em><em><u>H</u></em><em><u>E</u></em><em><u>L</u></em><em><u>P</u></em><em><u>S</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u>༒</u></em>
<em><u>༒</u></em><em><u>M</u></em><em><u>A</u></em><em><u>R</u></em><em><u>K</u></em><em><u> </u></em><em><u>M</u></em><em><u>E</u></em><em><u> </u></em><em><u>A</u></em><em><u>S</u></em><em><u> </u></em><em><u>B</u></em><em><u>R</u></em><em><u>A</u></em><em><u>I</u></em><em><u>N</u></em><em><u>L</u></em><em><u>I</u></em><em><u>E</u></em><em><u>S</u></em><em><u>T</u></em><em><u>༒</u></em>
Answer: adding
Explanation:
Because it takes thermal energy to power it
Molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Given,
Moles of metal M = 0.300 moles
weight of mF₂ formed =23.4g
we have to find the name of element m...
Now,
m + F₂ → mF₂
1 mole of m reacts with 1 mole of F₂ (or 2 molecule of flourine) to form 1 mole of mF₂
Hence,
0.300 moles of m reacts with 0.300 moles of F₂ to form 0.300 moles of mF₂.
Hence,
23.4 g = 0.300 moles of mf2
0.300 × 38g + 0.300 × m = 23.4 g
Hence
m = 40 g
So, molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Thus, from the above conclusion we can say that, name of element m is Calcium. which is represented by the symbol Ca.
Learn more about Calcium here:brainly.com/question/26636816
#SPJ4
Answer:
Lustrous is NOT a property of metal