We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+ + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
z= 4.81x10^-7
∴[H+] = 4.81x10^-7
when PH equation is:
PH= -㏒[H+]
= -㏒(4.81x10^-7) = 6.32
Answer:
b. ΔH and ΔS are negative at all temperatures .
Explanation:
During the process of condensation ,
The gaseous state convert to liquid state ,
Hence , the entropy of the system reduces , i.e. , the randomness decreases .
And the value for entropy is negative ,
hence ,
Δ S = negative ,
Δ H = negative ,
Since ,
The heat is releasing from system .
hence , the most appropriate option will be ΔH and ΔS are negative at all temperatures .
Answer:
Hello attached below is the data found in Aleks Data tab
answer :
i) N0
ii) N0
iii) YES , pH of highest solubility = 5
Explanation:
i) For CuBr
solubility does not change with pH hence answer = NO
ii) For MgCl2
solubility does not change with pH hence the answer = NO
iii) For Ba(OH) 2
Solubility does change with pH hence the answer = YES
and the pH at which the highest solubility will occur is = 5
attached below is the reason for the answers given
Answer:
Approximately 56.8 liters.
Assumption: this gas is an ideal gas, and this change in temperature is an isobaric process.
Explanation:
Assume that the gas here acts like an ideal gas. Assume that this process is isobaric (in other words, pressure on the gas stays the same.) By Charles's Law, the volume of an ideal gas is proportional to its absolute temperature when its pressure is constant. In other words
,
where
is the final volume,
is the initial volume,
is the final temperature in degrees Kelvins.
is the initial temperature in degrees Kelvins.
Convert the temperatures to degrees Kelvins:
.
.
Apply Charles's Law to find the new volume of this gas:
.