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rusak2 [61]
3 years ago
9

Iodine-131 decays with a half-life of 8.02

Chemistry
1 answer:
dlinn [17]3 years ago
3 0
Radioactive material undergoes 1st order decay kinetics.

For 1st order decay, half life = 0.693/k

where k = rate constant

k = 0.693/half life = 0.693/8.02 = 0.0864 day-1

Now, for 1st order reaction,
k = \frac{2.303}{t} X log \frac{initial.conc}{final.conc}

Given: t = 6.01d, initial conc. = 5mg

∴0.0864 = \frac{2.303}{6.01} X log \frac{5}{final.conc}
∴ final conc. = 2.975 mg
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233.1g

Explanation:

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learn more:

Number of moles brainly.com/question/1841136

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