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rusak2 [61]
3 years ago
9

Iodine-131 decays with a half-life of 8.02

Chemistry
1 answer:
dlinn [17]3 years ago
3 0
Radioactive material undergoes 1st order decay kinetics.

For 1st order decay, half life = 0.693/k

where k = rate constant

k = 0.693/half life = 0.693/8.02 = 0.0864 day-1

Now, for 1st order reaction,
k = \frac{2.303}{t} X log \frac{initial.conc}{final.conc}

Given: t = 6.01d, initial conc. = 5mg

∴0.0864 = \frac{2.303}{6.01} X log \frac{5}{final.conc}
∴ final conc. = 2.975 mg
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maw [93]

1. 100 C

2. Point B to C is the ices heat capacity

3. During the points D to E the bonds of the water molecules build up enough kinetic energy to break their intermolecular bonds (not intra), which can lead to gas.

4. Between points D and E the energy is being released the energy required is equivalent along the line.

5. Between point E and D the water is converting to water (condensation)

6. Energy is being released 2260 j/g

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5 0
3 years ago
H+(aq) + OH–(aq) → H2O(l) + 55.8 kJ In this reaction there is conservation of
pentagon [3]
In the equation given above, there is conservation of MASS, CHARGE AND ENERGY.
These three parameters are usually conserved during the course of chemical reactions. When any of these parameter experience a reduction during the course of chemical reaction, such loss is always gained by other elements involved in the same reaction, so that at the end of the day, they are not considered as lost. 
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3 years ago
En la electrosis del cloruro de sodio (Na Ci) el cloruro es atraido por elcatodo. Falso o verdadero. Y porque?
hram777 [196]

Answer:

Falso

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Los iones positivos se mueven hacia el cátodo, mientras que los iones negativos se mueven hacia el ánodo.

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8 0
3 years ago
Hurry PLEASE HELP!
avanturin [10]

B. 11,540

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

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\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

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N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Nt=25 g

No=100 g

t1/2=5770 years

\tt 25=100\dfrac{1}{2}^{T/5770}\\\\\dfrac{1}{4}=\dfrac{1}{2}^{T/5770}\\\\2=T/5770\rightarrowT=11540~years

7 0
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vladimir2022 [97]
1.Lithium has the greater ionization energy
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2 years ago
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