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HACTEHA [7]
1 year ago
7

A sample of 0.300 mol of a metal m reacts completely with excess fluorine to form 23.4 g of mf2. what element is represented by

the symbol m? (give its symbol).
Chemistry
1 answer:
Phoenix [80]1 year ago
5 0

Molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.

Given,

Moles of metal M = 0.300 moles

 weight of mF₂ formed =23.4g

we have to find the name of element m...

Now,

 m + F₂ → mF₂

1 mole of m reacts with 1 mole of F₂ (or 2 molecule of flourine) to form 1 mole of mF₂

Hence,

 0.300 moles of m reacts with 0.300 moles of F₂ to form 0.300 moles of mF₂.

 

Hence,

 23.4 g = 0.300 moles of mf2

0.300 × 38g + 0.300 × m = 23.4 g

Hence

 m = 40 g

So, molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.

 Thus, from the above conclusion we can say that, name of element m is Calcium. which is represented by the symbol Ca.

Learn more about Calcium here:brainly.com/question/26636816

#SPJ4

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Down below

Explanation:

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8 0
3 years ago
What is the vapor pressure of the solution if 35.0 g of water is dissolved in 100.0 g of ethyl alcohol at 25 ∘C? The vapor press
masya89 [10]

<u>Answer:</u> The vapor pressure of the solution is 43.55 mmHg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For water:</u>

Given mass of water = 35.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{35.0g}{18g/mol}=1.944mol

  • <u>For ethyl alcohol:</u>

Given mass of ethyl alcohol = 100.0 g

Molar mass of ethyl alcohol = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of ethyl alcohol}=\frac{100.0g}{46g/mol}=2.174mol

Total moles of solution = [1.944 = 2.174] moles = 4.118 moles

  • Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

<u>For water:</u>

\chi_{\text{water}}=\frac{n_{\text{water}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}

\chi_{water}=\frac{1.944}{4.118}=0.472

<u>For ethyl alcohol:</u>

\chi_{\text{ethyl alcohol}}=\frac{n_{\text{ethyl alcohol}}}{n_{\text{water}}+n_{\text{ethyl alcohol}}}

\chi_{\text{ethyl alcohol}}=\frac{2.174}{4.118}=0.528

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the vapor pressure of the solution, we use the law given by Dalton, which is:

P_T=\sum_{i=1}^n (p_i\times \chi_i)

Or,

P_T=[(p_{\text{water}}\times \chi_{\text{water}})+(p_{\text{ethyl alcohol}}\times \chi_{\text{ethyl alcohol}}

We are given:

Vapor pressure of water = 23.8 mmHg

Vapor pressure of ethyl alcohol = 61.2 mmHg

Putting values in above equation, we get:

p_T=[(23.8\times 0.472)+(61.2\times 0.528)]\\\\p_T=43.55mmHg

Hence, the vapor pressure of the solution is 43.55 mmHg

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