A+20 N force acts on a car and at the same time, a -30 N force acts on the
1 answer:
Answer:
-10 N, not balanced
Explanation:
Force is a vector quantity, so in order to find the net force on an object, we must use vector addition rule.
This means that if two forces acting on an object along the same line, we have to choose one direction as positive, and write the two forces with the correct sign.
In this problem, we have two forces acting along a line on the car:
- A first force of
- A second force of
Therefore, the net force on the car is:
Moreover, the net force on an object is said to be "balanced" if it is zero: in this case, it is not zero, so it is not balanced.
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The net force acting on the bicyclist is 11.022 Newton.
<u>Given the following data:</u>
- Mass of bicyclist = 66 kg
- Initial velocity = 0.50 m/s
- Initial velocity = 1.50 m/s
- Distance traveled = 6.0 meters
To find the net force acting on the bicyclist, we would apply Newton's Second Law of Motion:
Mathematically, Newton's Second Law of Motion is given by this formula;
×
First of all, we would determine the acceleration by using the third equation of motion;
Acceleration, a = 0.167
Now, we can find the net force acting on the bicyclist:
×
<em>Force </em><em>= </em><em>11.022 Newton</em>
Therefore, the net force acting on the bicyclist is 11.022 Newton.
Read more here: brainly.com/question/24029674
The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.
<h3>What is Columb's law?</h3>The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.
They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.
The given data in the problem is;
q₁ is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C
F is the repulsive force = 36 mN =36 ×10⁶ N
d is the distance = 0.70 m
The Coulomb force is found as;
Hence, the magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C.
To learn more about Coulomb's law, refer to the link;
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