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Masja [62]
2 years ago
5

A+20 N force acts on a car and at the same time, a -30 N force acts on the

Physics
1 answer:
katovenus [111]2 years ago
5 0

Answer:

-10 N, not balanced

Explanation:

Force is a vector quantity, so in order to find the net force on an object, we must use vector addition rule.

This means that if two forces acting on an object along the same line, we have to choose one direction as positive, and write the two forces with the correct sign.

In this problem, we have two forces acting along a line on the car:

- A first force of

F_1 = +20 N

- A second force of

F_2=-30 N

Therefore, the net force on the car is:

\sum F=F_1+F_2=+20 +(-30)=-10 N

Moreover, the net force on an object is said to be "balanced" if it is zero: in this case, it is not zero, so it is not balanced.

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A stationary boat in the ocean is experiencing waves from a storm. The waves move at 59 km/h and have a wavelength of 145 m . Th
krek1111 [17]

Answer:

The time elapses until the boat is first at the trough of a wave is 4.46 seconds.

Explanation:

Speed of the wave, v = 59 km/h = 16.38 m/s

Wavelength of the wave, \lambda=145\ m

If f is the frequency of the wave. The frequency of a wave is given by :

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{16.38\ m/s}{145\ m}\\\\f=0.112\ Hz

The time period of the wave is given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.112\ Hz}\\\\T=8.92\ s

We need to find the time elapses until the boat is first at the trough of a wave. So, the time will be half of the time period of the wave.

T=\dfrac{8.92}{2}\\\\T=4.46\ s

Hence, this is the required solution.

5 0
3 years ago
1. A car moves 20 m/s east for 5 sec, 10m/s north for 10 sec and then 30m/s west for 5 sec. Calculate a) displacement
aalyn [17]

Try the solutions described in the attached picture, note the answers are marked with green colour.

3 0
2 years ago
What is undefined <br> I need help I don't understand this question
Wittaler [7]
(4/9-9) and (4/0) are undefined as you can not divide by the value of 0.
6 0
3 years ago
Read 2 more answers
5. Put these in order from least to greatest resistance:
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8 0
3 years ago
A 0.43-kg object mass attached to a spring whose spring constant is 561 N/m executes simple harmonic motion. If its maximum spee
VLD [36.1K]

Answer:

0.22 m

Explanation:

m = 0.43 kg, K = 561 N/m

Vmax = 8 m/s

Let the amplitude of the oscillations be A.

The formula for the angular frequency of oscillation sis given by

\omega  = \sqrt{\frac{K}{m}}

\omega  = \sqrt{\frac{561}{0.43}}

ω = 36.1 rad/s

The formula for the maximum velocity is given by

Vmax = ω x A

A = Vmax / ω

A = 8 / 36.1 = 0.22 m

4 0
2 years ago
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