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vivado [14]
2 years ago
7

How do I do this it is for science and I do not want to fail​

Physics
1 answer:
Jlenok [28]2 years ago
8 0
The small circle has 2 on each side and the rest have 8 as you can see but put them into pairs. you know how many to put based on the amount of protons (:
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Fluorescence occurs when an object absorbs ____________________ and immediately releases the energy as visible light.
soldier1979 [14.2K]

Answer:

The answer should be light or other electromagnetic radiation

Explanation:

Such as x-rays or other things like that.

<em>-Hope This Helps!</em>

<em>-Justin:)</em>

5 0
2 years ago
PLZ HELP GUYS PLZ!!!!! The answer is not motion, particles.
harina [27]

Answer:

Energy

Explanation:

4 0
3 years ago
If an X-ray beam of wavelength 1.4 × 10-10 m makes an angle of 20° with a set of planes in a crystal causing first order constru
Flura [38]

Answer:

43.16°

Explanation:

λ = Wavelength = 1.4×10⁻¹⁰ m

θ₁ = 20°

n can be any integer

d = distance between the two slits

Since for the first bright fringe, n₁ = 1

n₂ = 2 for second order line

The relation between the distance of the slits and the angle through which it is passed is:

dsinθ=nλ

As d and λ are constant

\frac{n_1\lambda}{sin \theta_1}=\frac{n_2\lambda}{sin \theta_2}\\\Rightarrow \frac{1}{sin20}=\frac{2}{sin\theta_2}\\\Rightarrow sin\theta_2=\frac{2}{\frac{1}{sin20}}\\\Rightarrow \theta_2=sin^{-1}{\frac{2}{\frac{1}{sin20}}}\\\Rightarrow \theta_2=43.16^{\circ}

∴ Angle by which the second order line appear is 43.16°

5 0
2 years ago
A small grinding wheel has a moment of inertia of 4.0*10-5kgm2. What net torque must be applied to the wheel for its angular acc
kvv77 [185]

Hi there!

We can use the rotational equivalent of Newton's Second Law:

\huge\boxed{\Sigma \tau = I \alpha}

Στ = Net Torque (Nm)

I = Moment of inertia (kgm²)

α = Angular acceleration (rad/sec²)

We can plug in the given values to solve.

\Sigma \tau = (4 * 10^{-5})(150) = \boxed{0.006 Nm}

4 0
2 years ago
A 0.150 kg baseball has 118 j of KE. how fast is the ball moving?(unit=m/s)
MrRissso [65]

Answer:

Explanation 118 = (1/2) * 0.15 * v² 118 = 0.075 * v² v² = 1573.33 m/s ... since KE = m/2*V^2 , then : V = √2KE/m = √20*118/1.5 = 39.67 m//sec ( 142.8 km/h ; 88.75 mph).:

4 0
3 years ago
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