The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
D
Step-by-step explanation:
90-33=57
57-1=56
56/2=28
28
Answer:
x < -3 or x > 3
second answer choice
Step-by-step explanation:
The symbol "∨" between p and q represents a disjunction and can be replaced with the word "or" to turn p ∨ q into p or q.
Plug in x < -3 in for p and x > 3 for q, and now you have:
x < -3 or x > 3
which is the same as the second answer choice.
So, the answer is x < -3 or x > 3, or the second answer choice.
I hope you find my answer helpful.
Answer:
its 400 cuz 0.1 is tenth
Step-by-step explanation:
Answer:
a. 15 on top 8 on bottom
b. 2 on top -3 on bottom
c. 4 and 2
d. 4 on top 8.5 on bottom
e. -3 and -4
Step-by-step explanation:
multiply the two numbers on the sides to get the top answer and add them together to get the bottom answer.
