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2 years ago

Is 8.6666 a irrational or rational

Mathematics

2 answers:

kondaur [170]2 years ago

6 0

Rational ffmnfndndnnfndd

Mkey [24]2 years ago

3 0

Answer:

Rational.

Step-by-step explanation:

It is rational because irrational numbers are numbers that can't be written as fractions or as decimals that terminate or repeat. This is written as a repeating decimal, therefore it is rational.

I'm really sorry if this is wrong, but I'm absolutely certain its right.

Hope this helps! Have a great day!

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I need to know the answer and how to solve the question for #9 please

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Each numbered angle equals 37°.

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2 years ago

Rectangle poster is 3 times as long as wide perimeter is 24 in

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w= width

l = 3w

P = 2(l+w)

substitute

24 = 2(3w+w)

24 = 2(4w)

24 =8w

3 =w

The width is 3 inches

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3 years ago

(ASAP)Someone help me out please

ludmilkaskok [199]

Answer:

Y= 1/3x + 4

Step-by-step explanation:

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8 0

3 years ago

Alternate interior angles. if you are good at that help

mamaluj [8]

Answer:

Step-by-step explanation:

i think so,

(5x-54)⁰=(3x+16)⁰

5x-3x=16+54

2x=70

x=35⁰

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5x-54=5×35-54=121

hope it helps

have a nice day

8 0

2 years ago

Read 2 more answers

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

2 years ago