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nignag [31]
4 years ago
10

What can you caculate if you know the frequency and speed of a wave

Physics
1 answer:
Mila [183]4 years ago
4 0

Frequency and speed = wavelength.

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Calculate the minimum average power output necessary for a person to run up a 12.0 m long hillside, which is inclined at 25.0° a
Viktor [21]

Answer:

Power, P = 924.15 watts

Explanation:

Given that,

Length of the ramp, l = 12 m

Mass of the person, m = 55.8 kg

Angle between the inclined plane and the horizontal, \theta=25^{\circ}

Time, t = 3 s

Let h is the height of the hill from the horizontal,

h=l\ sin\theta

h=12\times \ sin(25)

h = 5.07 m

Let P is the power output necessary for a person to run up long hill side as :

P=\dfrac{E}{t}

P=\dfrac{mgh}{t}

P=\dfrac{55.8\times 9.8\times 5.07}{3}

P = 924.15 watts

So, the minimum average power output necessary for a person to run up is 924.15 watts. Hence, this is the required solution.

3 0
3 years ago
If the force acting on a body of mass 4 kg is doubled. by how much will the acceleration change?
mr Goodwill [35]

Answer:

The acceleration will also double

Explanation:

F = m*a

a = F/m

plugging in sample numbers to prove

a= 100/4   = 25

a = 200/4 = 50

3 0
3 years ago
You are driving at 23 m/s when you see a red light ahead. Your car is capable of decelerating at a rate of 3.41 m/s2 and it take
Pavel [41]

Answer:

39.2 m

Explanation:

i think

4 0
3 years ago
What concept or principle best explains why
andreev551 [17]

Answer:

d. Newton's first law

I hope this helps you

5 0
3 years ago
The earth's radius is 6.37×106m; it rotates once every 24 hours.What is the speed of a point on the earth's surface located at 3
bagirrra123 [75]

Answer:

v = 120 m/s

Explanation:

We are given;

earth's radius; r = 6.37 × 10^(6) m

Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s

Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.

The angle will be;

θ = ¾ × 90

θ = 67.5

¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.

The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:

v = r(cos θ) × ω

v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)

v = 117.22 m/s

Approximation to 2 sig. figures gives;

v = 120 m/s

8 0
3 years ago
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