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melisa1 [442]
3 years ago
12

A pH increases, what happens to the hydroxide ion concentration?

Chemistry
1 answer:
Tanzania [10]3 years ago
6 0
When ph decreases the hydrogen ion concentration increases because ph = - log (H)
Likewise, the other way around is true (when hydrogen ion concentration increases, pH decreases).
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You are starting with 2 pounds of 30% acetic acid solution. You want to dilute
Tpy6a [65]

Answer:

The mass of water to be added is 2 pounds

Explanation:

The given parameters are;

The mass of the given solution = 2 pounds

The concentration of the given solution = 30%

The desired concentration of the solution = 15%

The mass, m of the acetic acid in the given solution = 30% × 2 pounds

m = 30/100 × 2 pounds = 0.6 pounds

To make a 15% acetic acid solution of acetic acid, the mass X of the required volume, is given as follows;

15% of X = 0.6 pounds

15/100 × X = 3/20 × 0.6 pounds

∴ The mass of the solution required  X = 0.6 × 20/3 = 4 pounds

The mass of the solution that will contain 0.6 pounds of acetic acid giving a 15% acetic acid solution is 4 pounds

Therefore, the mass of water to be added to the original solution to make the a 15% acetic acid solution is 2 pounds.

8 0
4 years ago
Natural selection is defined as_____ a. the changes that occur in a population that do not affect survival. b. the changes in th
Dmitry_Shevchenko [17]

Answer:

The answer is B, natural selection is the process whereby <u>organisms better adapted to their environment tend to survive and produce more offspring</u>. The theory of its action was first fully expounded by Charles Darwin and is now believed to be the main process that brings about <u>evolution</u>.

5 0
4 years ago
If you dilute 125 mL of a 2.5 M solution of Lici to 1.0 L, determine the new
Rama09 [41]

Answer:

0.31M is the new concentration of the solution

Explanation:

The solution is diluted from 125mL to 1.0L = 1000mL. The dilution is of:

1000mL / 125mL = 8 times.

That means the concentration of the diluted solution is 8 times lower than the original solution. That is:

2.5M / 8 times =

<h3>0.31M is the new concentration of the solution</h3>
7 0
3 years ago
5.) During the electrolysis of dilute copper(II)sulphate solution using carbon 1 point
Neporo4naja [7]

Answer:

A g I need the answer too

Explanation:

6 0
3 years ago
A 575.4575.4 mL sample of carbon dioxide was heated to 377377 K. If the volume of the carbon dioxide sample at 377377 K is 824.7
Margaret [11]

Answer:

263 K

Explanation:

Assuming ideal behaviour and constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

  • T₁V₂=T₂V₁

In this case:

  • T₁ = ?
  • V₂ = 824.7 mL
  • T₂ = 377 K
  • V₁ = 575.45 mL

We <u>input the data</u>:

  • T₁ * 824.7 mL = 377 K * 575.45 mL

And <u>solve for T₁</u>:

  • T₁ = 263 K
3 0
3 years ago
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