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Nostrana [21]
2 years ago
13

Write a variable expression that represents the following word phrase: three more than two times the difference of x and one.​

Chemistry
2 answers:
Inga [223]2 years ago
5 0

Convert the wordphrase to expression

\\ \rm\longmapsto 2(x-1)+3

\\ \rm\longmapsto 2x-2+3

\\ \rm\longmapsto 2x+1

wel2 years ago
3 0

Answer:

  • ⇛2(x−1)+3
  • ⇛2x−2+3
  • ⇛2x+1
  • ⇛2(x-1)+3

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The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
azamat

Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

V_{copper}=0.122cm^3

(c) \rho _{coin}=15.94g/cm^3

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

Best regards.

3 0
3 years ago
Read 2 more answers
In the combined gas law, if the volume is decreased, what happens to the temperature if pressure remains constant?
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The correct answer is A. In the combined gas law, if the volume is decreased and the pressure is constant, then the temperature decreases.

 <span>P1V1/ T1 = P2V2 / T2</span>

 <span>Assume the volume decrease by half; V2 = V1/2</span>

 <span>P1V1/ T1 = P2V1 /2 T2</span>

 <span>Cancelling terms,</span>

 <span>1/T1 = 1/2 T2</span>

T2 = T1/2

 <span>Thus, the temperature decreased.</span>

8 0
3 years ago
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