All categories

3 years ago

How many moles of calcium are there in 5.74 x 1022 atoms of calcium?

Chemistry

1 answer:

igor_vitrenko [27]3 years ago

6 0

Answer:

0.095 moles of Calcium is there in 5.74 x 1022 atoms of calcium.

Explanation:

As we know, 6.023*10^23 atoms of an element is equal to its atomic weight.

And, 6.023*10^23 atoms of an element is also equal to 1 mole of the element.

We have,

6.023*10^23 atoms of element calcium equals to 1 mole of Calcium
5.74*10^22 atoms of element calcium equals to

(1/(6.023*10^.23)) * 5.74*10^22 moles of calcium

Therefore,

5.74 x 1022 atoms of calcium= 0.095 moles of calcium.

You might be interested in

WILL MARK BRANLIEST FOR CORRECT ANSWER! Given the following equation, write the expression for its relative rate.

USPshnik [31]

$\tt -\dfrac{1}{2}\dfrac{d[N_2O]}{dt}=\dfrac{1}{2}\dfrac{d[N_2]}{dt}=\dfrac{1}{1}\dfrac{d[O_2]}{dt}$

<h3>Further explanation</h3>

Reaction

2N2O(g) — 2N2(g) + O2(g)

Required

relative rate

Solution

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.

so the relative rates for the reaction above are :

$\tt -\dfrac{1}{2}\dfrac{d[N_2O]}{dt}=\dfrac{1}{2}\dfrac{d[N_2]}{dt}=\dfrac{1}{1}\dfrac{d[O_2]}{dt}$

7 0

2 years ago

In order to wash out the impurity, you looked up some sketchy method from 1952 which Hank Pym wrote during his Ph. D. under E. J

Eva8 [605]

Answer:

516.24

Explanation:

The solved solution is in the attached document.

8 0

2 years ago

Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu

pochemuha

Answer : The volume of $CO_2$ will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

$HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2$

First we have to calculate the mass of $HCO_3^-$ in tablet.

$\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g$

Now we have to calculate the moles of $HCO_3^-$ .

Molar mass of $HCO_3^-$ = 1 + 12 + 3(16) = 61 g/mole

$\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles$

Now we have to calculate the moles of $CO_2$ .

From the balanced chemical reaction, we conclude that

As, 1 mole of $HCO_3^-$ react to give 1 mole of $CO_2$

So, 0.0202 mole of $HCO_3^-$ react to give 0.0202 mole of $CO_2$

The moles of $CO_2$ = 0.0202 mole

Now we have to calculate the volume of $CO_2$ by using ideal gas equation.

$PV=nRT$

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = $37^oC=273+37=310K$

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

$(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)$

$V=0.51411L=514.11ml$

Therefore, the volume of $CO_2$ will be, 514.11 ml

6 0

2 years ago

Match the condensed structural diagrams with the correct names

AleksAgata [21]

Answer:

Here's what I get

Explanation:

1. Names

I. CH₃-CH₂-COOH = 49. propanoic acid

II. CH₃-CH₂-OH = 46. ethanol

III. CH₃-COO-CH₂-CH₂-CH₃ = 47. propyl ethanoate

IV. H-O-CH₂-CH₂-CH₃ = 48. propan-1-ol

V. H-COO-CH₃ = 51. methyl methanoate

VI. CH₃-COOH = 50. ethanoic acid

2. Precursors

52. methyl propionate ⇒ methanol + propanoic acid

53. ethyl methanoate ⇒ ethanol + methanoic acid

6 0

3 years ago

Lysol Power Toilet Bowl Cleaner contains 9.5% hydrochloric acid. Explain why this would be necessary to clean toilet bowls that

Romashka [77]

Answer:

The acid will absolutely remove the hard water deposits that are trapping the stains. The longer it soaks, the less you have to scrub. It works for hard water stains, limescale, and rust!

Explanation:

hope this helped you out.

8 0

2 years ago