Answer:
0.087
Step-by-step explanation:
Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:
= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:
X₅ ~ Poisson (20 (5/60))
X₅ ~ Poisson (1.6667)
Formula for computing probabilities for Poisson is as follows:
P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!
P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! = (e^-1.6667)((1.6667²)/3!)
P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)
P(X₅= 3) = (2.718^(-1.6667))0.46
P(X₅= 3) = 0.1889×0.46
P(X₅= 3) = 0.086894
P(X₅= 3) = 0.087
Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.
<span>[2(3+5)-2(4+1)]5
=</span><span>[2(8)-2(5)]5
=</span><span>[16-10]5
=6*5
=30</span>
Answer:
-1.23 is the correct answer
Step-by-step explanation:
-0.3×4.1 = -1.23 because when multiplying the negative is given to the answer unless there are 2 negatives in which case they cancel out.
8•25•23=
25 eight times is 25 four times + 25 four more times
((25•4)+(25•4))•23= (100+100)•23= 200•23= 2•23•100= 46•100= 4,600
