Answer:
0.928 M
Explanation:
The concentration of acid can be determined by using the volume used and the concentration and volume used of base.
We will use the law of equivalence of moles.
M₁V₁=M₂V₂
M₁ = concentration of base used
V₁ = volume of base used
M₂ = concentration of acid used =? (to be determined)
V₂ = volume of acid used
The initial concentration of KOH used is diluted so let us find the final concentration of KOH after dilution
initial moles = final moles
initial concentration X initial volume = final concentration X final volume
6.2 X 2.1 = 250 X final concentration
final concentration = 0.052 M = M₁
V₁ = 36.9 mL
V₂ = 6.2 mL
Here with each mole of phosphoric acid three moles of KOH are used.
Therefore
3 M₁V₁ = M₂V₂
M₂ = 
The answer to this question would most definitely be the last one
Answer:
- The main idea behind MADs is that they use the principle that metallic objects (submarines) interfere in the magnetic lines of Earth forces. And this equipment detects this anomaly.
- Submarines can be detected by using MADs
- The history of MAD development
In 1917 the interest in the detection of submarines started with the study hydrophones. Then in 1918, the U.S. considered to use the magnetism in this area but it did not result to be practical as it had a limited detection range.
Then by 1941 in Britain and in U.S. developed magnetic detection devices to measure Earth’s magnetic field, so after that in 1943 MADs were installed in ASW aircrafts.
Due to the limited range and its lack of ability to detect the magnetic variance from different sources, MAD started to be used in combination with sonobuoys. This combination allowed an aircraft to localize submarines with the confirmation of sonobuoys.
Explanation:
MADs are Magnetic Anomaly Detectors. Their function is to detect anomaly in the Earth’s magnetic field caused by submarines.
Submarines are made of ferrous metal which contain domains that are tiny magnets form of iron molecules. This material creates a disturbance that can be detected in the magnetic field.
