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lapo4ka [179]
2 years ago
6

Which conclusion is supported by the information in the graph?

Chemistry
1 answer:
Molodets [167]2 years ago
4 0

Answer:

A. The cost of producing a kilowatt of power with fuel cell will be less than $30 in 2015

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How many moles in 4 g of Ca3N2?<br><br> .027 mol<br><br> .613 mol<br><br> 2.05 mol<br><br> .760 mol
Arada [10]

Answer:

0.027mole

Explanation:

3 0
1 year ago
UHHH helpppp maya cause uh she d.a.n.g d.u.m.b.
inna [77]

Answer:

17

Explanation:

the mass number of the element which is protons and neutrons is 17+18=35

electronic configuration is 2, 8, 7

valency of the element is 1 therefore the atomic number is 17

6 0
2 years ago
Read 2 more answers
What is the term for a liquid composed of polar molecules?
IrinaVladis [17]
A dissolving liquid composed of polar molecules is a polar solvent.

The distinction of polar and non-polar liquids is important because the like dissolves like rule. This rule states that the solubility is greater when the polarity of the liquid is similar to the polarity of the solute.

So, to dissolve polar compounds (e.g. ionic compounds) you should use polar solvents (e.g. water).

Answer: polar solvent
7 0
3 years ago
To find the Ce4+ content in a solid sample, 4.3718 g of the solid sample were dissolved and treated with excess iodate to precip
gulaghasi [49]

Answer:

3.43 %

Explanation:

We need  to calculate first the number of moles of CeO2 produced in the combustion. Given its formula we know how many moles of Ce atom are present. From there calculate the mass this number of moles this represent and then one can calculate the percentage.

0.1848 g CeO2 x 1 mol CeO2/172.114g = 0.00107 mol CeO2

0.00107 mol CeO2 x 1 mol Ce/ 1 mol CeO2 = 0.00107 mol Ce

.00107 mol Ce x 140.116 g Ce/ mol  =  0.150 g Ce

0.150 g Ce/ 4.3718 g sample  x 100 = 3.43 %

5 0
3 years ago
Read 2 more answers
How many grams of CO2 are in 2.1 mol of the compound? a) 21.0g c) 66.0g
Lilit [14]
1 mole CO2 = 44.0096 grams CO2


<span>2.1 mol CO2 x (44.0096 grams CO2/1 mole CO2) = 92.4 grams CO2</span>
8 0
3 years ago
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