Whats the area of the figure?

In 2008, data from the Center for Disease Control revealed that 28.5% of all male teenagers, aged 18-19 and attending U.S. colle

m_a_m_a [10]

Answer:

a) H0 : u = 28.5%

H1 : u < 28.5%

b) critical value = - 1.645

c) test statistic Z= - 1.41

d) Fail to reject H0

e) There is not enough evidence to support the professor's claim.

Step-by-step explanation:

Given:

P = 28.5% ≈ 0.285

X = 210

n = 800

$p' = \frac{X}{n} = \frac{210}{800} = 0.2625$

Level of significance = 0.05

a) The null and alternative hypotheses are:

H0 : u = 28.5%

H1 : u < 28.5%

b) Given a 0.05 significance level.

This is a left tailed test.

The critical value =

$-Z_0.05 = -1.645$

The critical value = -1.645

c) Calculating the test statistic, we have:

$Z = \frac{p' - P}{\sqrt{\frac{P(1-P)}{n}}}$

$Z = \frac{0.2625 - 0.285}{\sqrt{\frac{28.5(1-28.5)}{800}}}$

Z = -1.41

d) Decision:

We fail to reject null hypothesis H0, since Z = -1.41 is not in the rejection region, <1.645

e) There is not enough evidence to support the professor's claim that the proportion of obese male teenagers decreased.

5 0

3 years ago

A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes

Pavel [41]

Answer:

0.818

Step-by-step explanation:

Since the shipment has a ton of aspirin tablets, we can assume that we pick 13 of them with reposition, because the probability shoudn't change dramatically from the probability of picking without reposition if we do so.

We call D the amount of defective tablets. If we assume that we pick the tablets with reposition, then we obtain that D is a random variable of Binomial distribution with parameters 13 and 0.6 (the probability of picking a defective tablet).

We want D to be at most one. To calculate the probability of that event we add up the probability of D being equal to 0 and the probability of D being equal to one. Since D is binomial, we have

$P(D = 0) = (1-0.06)^{13} = 0.447$
$P(D = 1) = {13 \choose 1} * 0.06^1 * (1-0.06)^{12} = 13*0.06*0.94^{12} = 0.371$

We conclude that

$P(D \leq 1) = P(D = 0) + P(D = 1) = 0.447+0.371 = 0.818$

Hence, the shipment will be accepted with probability 0.818

I hope this helps you!

6 0

3 years ago

A recipe calls for 5 deciliters of water and 236 milliliters of milk. How many milliliters of liquid does the recipe call for in

olya-2409 [2.1K]

1 deciliter is one-tenth of a liter and 1 milliliter is one-thousandth of a liter.
So: 1 liter = 10 deciliter = 100 centiliter = 1000 milliliter

This means that 1 deciliter is equal to 100 milliliters.
Based on the above:

5 deciliters = 500 milliliters
500+236 = 736

The recipe calls for 736 milliliters of liquid in total.

3 0

3 years ago

The flow of financial data through the accounting information system does NOT include a. receiving payment for all accounts rece

Leokris [45]

Answer:

a. receiving payment for all accounts receivable.

Step-by-step explanation:

The flow of financial data through the accounting information system does NOT include - receiving payment for all accounts receivable.

The flow of data through the accounting information system includes analyzing transactions, journalizing and posting transactions and preparing a trial balance.

7 0

3 years ago

What's the answer to this problem

zhenek [66]

The answer is 0.08 or you could say 8 * 10^-2.

Reasoning..
6.4 * 10^3 = 6400
8 * 10^4 = 80000

Divide those two numbers like shown in the problem and boom!

6 0

3 years ago

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