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Gala2k [10]
3 years ago
6

892.970 cm2 to four significant figures

Chemistry
1 answer:
Sophie [7]3 years ago
5 0

Answer:

Explanation:

There is a trick to this. Counting out the 4 places is easy enough.

Start at the 8 and count to your right. You land on the nine, but that is not quite your answer.

The 7 influences the 9 and the nine gets bumped up which makes it a 10. but you just record the zero part. The 1 gets added to the 2.

That in turn influences the 2 which makes it a three. So your answer is

893.0

The trick is that you must include the 0. You are guaranteeing that you know the accuracy of the fourth place. Weird but true.

It helps just slight to convert this to scientific notation.

8.9297 * 10^2  = 8.930 * 10^2

You get the same rounding problem as discussed above, but it might be a little easier to see.

You get the same answer and you have to go through the same steps.

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B and C

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The correct answer is Condensation and Deposition

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How many moles are in 1.05 g of gold (Au)?
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Answer:

0.005 mol

Explanation:

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

From the question ,

w = given mass of Gold = 1.05 g ,

m = molecular mass of Gold = 197 g/mol

<u>Hence , moles can be calculated as -</u>

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A solution has a pOH of 8.20. What is the concentration of H3O+?
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.000001585

Explanation:

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g Determine the empirical formula for a compound that contains C, H and O. It contains 40.92% C, 4.58% H, and 54.50% O by mass.
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Answer:

The empirical formula for the compound is C3H4O3

Explanation:

The following data were obtained from the question:

Carbon (C) = 40.92%

Hydrogen (H) = 4.58%

Oxygen (O) = 54.50%

The empirical formula for the compound can be obtained as follow:

C = 40.92%

H = 4.58%

O = 54.50%

Divide by their molar mass

C = 40.92/12 = 3.41

H = 4.58/1 = 4.58

O = 54.50/16 = 3.41

Divide by the smallest i.e 3.41

C = 3.41/3.41 = 1

H = 4.58/3.41 = 1.3

O = 3.41/3.41 = 1

Multiply through by 3 to express in whole number

C = 1 x 3 = 3

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O = 1 x 3 = 3

The empirical formula for the compound is C3H4O3

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