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lyudmila [28]
3 years ago
8

Draw the kinetic and thermodynamic enolates formed when 3-methylbutan-2-one (methyl isopropyl ketone) is treated with base. Incl

ude charges. Draw the oxyanion species; do not draw carbanion resonance forms.
Chemistry
1 answer:
VARVARA [1.3K]3 years ago
7 0
Hmmm..... ok i will see my answer
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3 years ago
4. The following occurs when heat energy is removed: Gas --A-&gt; Liquid-B--&gt; Solid.
Misha Larkins [42]

Answer: The phase change for A and B respectively is condensation, freezing.

Explanation:

A process in which gaseous state of a substance converts into liquid state is called condensation.

For example, conversion of steam into water.

A process in which liquid state of a substance converts into solid state is called freezing.

For example, conversion of liquid water into ice.

Thus, we can conclude that the phase change for A and B respectively is condensation and freezing.

6 0
3 years ago
Draw the structure of the major organic product isolated from the reaction of 3-hexyne with hydrogen (1 mol), Lindlar palladium.
ohaa [14]

Answer:

See explanation and image attached

Explanation:

When 1 mole of hydrogen is added to 3-hexyne, the addition occurs on the same face or side of the triple bond to yield cis-2-hexene in the presence of lindlar catalyst which prevents further hydrogenation. This is known as syn addition.

The syn addition is achieved because the hydrogen molecule is first adsorbed on the surface of the palladium metal and is subsequently attached to the same face of the triple bond in 3-hexyne as shown in the image attached to this answer.

6 0
3 years ago
What grey rock that has crinoids and brachiopods reacts to hydrochloric acid?
Anon25 [30]
The rock is limestone, I hope this helps!!
5 0
3 years ago
Read 2 more answers
A compound is composed of only C, H, and O. The combustion of a .519-g sample of the compound yields 1.24 g of CO_2 and .255 g o
Kay [80]

Answer:

Empirical formula is C₃H₃O.

Explanation:

Given data:

Mass of compound = 0.519 g

Mass of CO₂ = 1.24 g

Mass of H₂O = 0.255 g

Empirical formula = ?

Solution:

%age of C,H,O

C = 1.24 g/0.519 × 12/44 ×100 = 65.5%

H = 0.255 g/0.519 × 2.016/18 ×100 =  5.6%

O = 100 - (65.5+5.6)

O = 28.9%

Number of gram atoms of H = 5.6 / 1.01 = 5.5

Number of gram atoms of O =  28.9 / 16 = 1.81

Number of gram atoms of C = 65.5 / 12 = 5.5

Atomic ratio:

            C                      :        H              :         O

          5.5/1.81              :       5.5/1.81     :       1.81/1.81

            3                      :        3              :        1

C : H : O = 3 : 3 : 1

Empirical formula is C₃H₃O.

8 0
4 years ago
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