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3 years ago

8

Draw the kinetic and thermodynamic enolates formed when 3-methylbutan-2-one (methyl isopropyl ketone) is treated with base. Incl

ude charges. Draw the oxyanion species; do not draw carbanion resonance forms.

1 answer:

VARVARA [1.3K]3 years ago

7 0

Hmmm..... ok i will see my answer

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How many neutrons are in Br-85

Travka [436]

There are 45 neutrons

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3 years ago

Consider the reaction.

Kaylis [27]

Answer:

2.1 x 10^-2

Explanation:

Divide 8.4 x 10^-3 x 8.4 x 10^-3 by 5.82 x 10^-2 and you end up with 2.1 x 10^-2

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3 years ago

The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react

Kazeer [188]

Answer:

The percent yield of chloro-ethane in the reaction is 82.98%.

Explanation:

$C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl$

Moles of ethane = $\frac{300.0 g}{30 g/mol}=10 mol$

Moles of chlorine gases = $\frac{650.0 g}{71 .0 g/mol}=9.1549 mol$

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

$\frac{1}{1}\times 9.1549 mol=9.1549 mol$ of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

$\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%$

The percent yield of chloro-ethane in the reaction is 82.98%.

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3 years ago

From the list below, determine which properties are for compounds. I. It takes a large amount of energy to separates the element

marshall27 [118]

All of them are properties of compounds except III.

for I, compounds are chemically combined together, so to separate them, we must use chemical methods like electrolysis or applying heat. These requires large amount of energy.

For II, they're always fixed. For example, in water (H2O), the ratio of hydrogen and oxygen is always 1:8 in mass. If there's some extra added, the substance becomes mixture instead of compounds.

For IV, after you chemically combined elements or compounds together, their properties are completely different. For example, iron can be attracted to magnets, but iron II sulphide does not.

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