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3 years ago

11

The seasons on earth are caused by its elliptical orbit around the sun. the seasons on earth are caused by its elliptical orbit

around the sun.
a. True
b. False

2 answers:

Korolek [52]3 years ago

7 0

That statement is false.
That statement is false.

Nady [450]3 years ago

6 0

The answer is b: false

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How much work would be needed to raise the payload from the surface of the moon (i.e., x = r) to the "end of the universe"?

meriva

Moon was rotation Earth or sun
it's own orbit . universe is not end

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4 years ago

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The drawings show three examples of the force with which someone pushes against a vertical wall. In each case the magnitude of t

Monica [59]

Complete Question

The complete question is shown on the

Answer:

The ascending order would be 2nd < 1st < 3rd

Explanation:

Generally the the Normal force is mathematically represented as

$Normal \ Force = Fsin \theta$

=> $Normal \ Force \ \alpha \ sin \theta$

For the first drawing the value $\theta$ is between that of the the second and the third drawing so the Normal force would also be between the normal forces of the second and the third drawing

For the second drawing whose value of $\theta$ is less than that of the first and the third the normal force would also be less than that of the first and third

For the the third drawing whose value is (90°) which is higher than the first and the second the normal force would also be higher than the first and the second

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3 years ago

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The term solstice translates as "Sun stop." Explain why this translation makes sense from an astronomical point of view. It make

adoni [48]

Answer:

It makes sense because on that the day the sun stops moving northward and starts moving southward

Explanation:

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4 years ago

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An ideal spring hangs from the ceiling. A 2.15 kg mass is hung from the spring, stretching the spring a distance d = 0.0895 m fr

Igoryamba

Answer:

The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

Explanation:

Given that,

Mass = 2.15 kg

Distance = 0.0895 m

Amplitude = 0.0235 m

We need to calculate the spring constant

Using newton's second law

$F= mg$

Where, f = restoring force

$kx=mg$

$k=\dfrac{mg}{x}$

Put the value into the formula

$k=\dfrac{2.15\times9.8}{0.0895}$

$k=235.41\ N/m$

We need to calculate the kinetic energy of the mass

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2$

Here, $v = A\omega$

$K.E=\dfrac{1}{2}m\times(A\omega)^2$

Here, $\omega=\sqrt{\dfrac{k}{m}}^2$

$K.E=\dfrac{1}{2}m\times A^2\sqrt{\dfrac{k}{m}}^2$

$K.E=\dfrac{1}{2}kA^2$

Put the value into the formula

$K.E=\dfrac{1}{2}\times235.41\times(0.0235)^2$

$K.E=0.06500\ J$

Hence, The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

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3 years ago

1. boiling point of water

melomori [17]

Answer:

what is the question. . .

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3 years ago