Question

a cart is initially moving at 0.5 m/s along a track. The cart comes to rest after traveling I m. The experiment is repeated on the same track, but now the cart is initially moving at I m/s. How far does the cart travel before coming to rest?

Answer 1

Answer:

4m

Explanation:

Using the kinematic equation;

For the first stage when the car is initially moving at 0.5m/s

definitely u = 0.5 m/s and v = 0

The cart comes to rest after traveling I m, ∴ (s) = 1m

the acceleration of the car can be expressed by applying the kinematic equation:

$v^2-u^2=2as$

making "a" the subject of the formula; we have:

$a = \frac{v^2-u^2}{2s}$

$a= \frac{0-(0.5 m/s)^2}{2(1m)}$

a = 0.125 m/s²

The experiment is repeated on the same track, but now the cart is initially moving at I m/s

i.e v = 1 m/s  and u=0

$S=\frac{v^2-u^2}{2a}$

$S= \frac{(1m/s)^2-0}{2(0.125m/s^2)}$

S = 4 m

∴ the cart traveled 4m  before coming to rest.

Answer 2

Explanation:

Below is an attachment containing the solution.