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Ymorist [56]
3 years ago
15

Ma puteti ajuta sa rezolv la fizica o problema ?

Physics
1 answer:
xxTIMURxx [149]3 years ago
7 0
Care este problema? Btw why are you speaking Romanian 
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A firm wants to determine the amount of frictional torque in their current line of grindstones, so they can redesign them to be
victus00 [196]

Answer:

a)- 1.799 rad/sec²

b)- 17.6 x 10ˉ³Nm

Explanation:

ω₀ = 720 rev/min x (1 min/60 sec) x (2π rad / 1 rev) =  24π rad/s

a) Assuming a constant angular acceleration, the formula will be

α = (ωf -ω₀) / t

As final state of the grindstone is at rest, so ωf =0

⇒ α = (0-24π) / 41.9 = - 1.799 rad/sec²

b)Moment of inertia I for a disk about its central axis

I = ½mr²  

where m=2kg and radius 'r'= 0.099m

I = ½(2)(0.099²)

I = 9.8 x 10ˉ³ kgm²

Next is to determine the frictional torque exerted on the grindstone, that caused it to stop, applying the rotational equivalent of the Newton's 2nd law:

τ = I α =>(9.8 x 10ˉ³)(- 1.799)

τ = - 17.6 x 10ˉ³Nm

(The negative sign indicates that the frictional torque opposes to the rotation of  the grindstone).

8 0
3 years ago
Mrs. Nogaki uses constant force to push a Costco shoping cart down the long store
Liono4ka [1.6K]
Figure B. The second option.
7 0
3 years ago
If Dave drives a car for 85 km/hr for 3 hours how for does he travel?
WITCHER [35]
85+85+85=255[3X85=255]


5 0
3 years ago
Read 2 more answers
Whats the formula of mass? example Density= mass/volume
DochEvi [55]
The formula for mass you can find from the density equation. Multiply the volume by both sides of the equation.

density = mass/volume

volume*density = mass 

And there you are :)
4 0
3 years ago
Read 2 more answers
Four kilograms of carbon monoxide (co) is contained in a rigid tank with a volume of 1 m3. the tank is fitted with a paddle whee
Alenkasestr [34]
Part (a): Specific volume
Specific volume, v = V/m, V = Volume of the tank, m = mass of CO in the tank
Therefore,
v = 1/4 = 0.25 m^3/kg

Part (b): Energy transferred in kJ
Work done, W = PΔt, where P = power = 14 W = 14 J/s, t = time = 1 hour = 60*60 = 3600 seconds
Therefore,
W = 14*3600 = 50400 J = 50.4 kJ

Part (c): Energy transferred by heat
ΔU = Q + W
Then,
Heat transferred by heat, Q = ΔU - W
But, ΔU = mΔu = 4 kg*10 kJ/kg = 40 kJ
Therefore,
Q = 40 - 50.4 = -10.4 kJ (negative sign indicates that heat is removed from the CO).
6 0
3 years ago
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