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Ymorist [56]
3 years ago
15

Ma puteti ajuta sa rezolv la fizica o problema ?

Physics
1 answer:
xxTIMURxx [149]3 years ago
7 0
Care este problema? Btw why are you speaking Romanian 
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Science: Physics AND Biology - Please help me with these, it's due tonight.
Ostrovityanka [42]
The answer to the first question is that plants make glucose and oxygen by taking in CO2 and H20.

The answer to the second question is having a heavier mass increases the force of a moving object. That is the Second Law of Motion, F = ma.
7 0
3 years ago
Hydrogen is found in three different states inside Jupiter, ______, liquid, and liquid ______.
tekilochka [14]

Answer:

gas, metal

Explanation:

The three states of by which hydrogen is found in Jupiter is made up of:

  1. Gaseous hydrogen
  2. liquid hydrogen
  3. liquid metal hydrogen

This is also the same states found in Saturn too.

The pressure inside the largest planet in our solar system is very great.

  • Hydrogen and helium makes up the entirety of the planet Jupiter.
  • It has been discovered that inside this planet, hydrogen often occurs as gas, liquid and metal
  • This is often attributed to the huge amount of pressure in the planet.
7 0
3 years ago
As an intern at an engineering firm, you are asked to measure the moment of inertia of a large wheel for rotation about an axis
klio [65]

Hi there!

We can begin by finding the acceleration of the block.

Use the kinematic equation:

d = v_0t + \frac{1}{2}at^2

The block starts from rest, so:

d = \frac{1}{2}at^2\\\\12 = \frac{1}{2}a(4^2)\\\\\frac{24}{16} = a = 1.5 m/s^2

Now, we can do a summation of forces of the block using Newton's Second Law:

F = ma = m_bg - T

mb = mass of the block

T = tension of string

Solve for tension:

T = m_bg - ma = 8.2(9.8) - 8.2(1.5) = 68.06 N

Now, we can do a summation of torques for the wheel:

\Sigma \tau = rF\\\\\Sigma\tau = rT

Rewrite:

I\alpha = rT

We solved that the linear acceleration is 1.5 m/s², so we can solve for the angular acceleration using the following:

\alpha = a/r\\\\\alpha = 1.5/.42= 3.57 rad/sec^2

Now, plug in the values into the equation:

I(3.57) = (0.42)(68.06)\\\\I = (0.42)(68.06)/(3.57) = \boxed{8.00 kgm^2}

8 0
2 years ago
john is using a pulley to lift the sail on his sailboat. the sail weighs 150N and he must lift it at 4.0m. how much work must be
gogolik [260]

The work done on the sail is 600 J

Explanation:

The work done to lift the sail is equal to the gain in gravitational potential energy of the sail, therefore is:

W=mg\Delta h

where

m is the mass of the sail

g is the acceleration of gravity

(mg) is the weight of the sail

\Delta h is the change in height of the sail

In this problem we have

mg = 150 N (weight)

\Delta h = 4.0 m

Substituting, we find the work done:

W=(150)(4.0)=600 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

5 0
3 years ago
A girl weighing 45kg is standing on the floor, exerting a downward force of 200N on the floor. The force exerted on her by the f
sukhopar [10]

Answer:

c.

Equal to 200 N..........

7 0
2 years ago
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