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zhuklara [117]
2 years ago
14

Sheila is baking a few cakes for the bake sale for her school. Each cake requires 2 ½ cups of sugar. How many cakes can she bake

if she has 7 ⅓ cups of sugar?
Provide answer and explain plz
Mathematics
1 answer:
Ber [7]2 years ago
5 0

Answer:

The answer is 2 cakes.

Step-by-step explanation:

What we know:

-Each cake requires 2 1/2 cups of sugar.

-Sheila has 7 1/3 cups of sugar.

What we need to know:

-How many cakes can Sheila make with 7 1/3 cups of sugar.

Remember:

-You must make a whole cake.

Show your work:

-I am going to convert the fraction into a decimal.

-2 1/2=2.5 and 7 1/3=7.3

-2 cakes will require 5 cups of sugar and you will remain with 2.3 cups of sugar.

-You <em>cannot </em>use 2.3 cups of sugar to make a cake. It must be in full.

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Riverdale High ordered 84 shirts with their logo on them. if 8 of the shirts were defective what percent of the shirts were not
Ymorist [56]

8 were defective.

Defective percent = 8/84 x 100 = 9.5238% were defective.

Percent not defective = 100% - 9.5238% = 90.4761%

Rounding to the nearest tenth 90.5% were not defective.

The question doesn’t say how to round the answer so you may need to round differently than I did.

8 0
3 years ago
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A simplifie 6 × ( - 24 ) ÷ ( -4 )​
kumpel [21]

\huge\textbf{Hey there!}

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8 0
2 years ago
Please help solve questions
Alekssandra [29.7K]

Take some points

  • 2x+3y<6
  • 3y<-2x+6
  • y<-2/3x+2

As here < sign present line will be dashed and shading should be done below the line

So

  • (1,1)
  • (1,0)
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Graph attached

4 0
2 years ago
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For the values a = 3.4 and b = 2.6, which are legs of a right triangle, find c, the hypotenuse, to the nearest tenth.
sammy [17]
C^2 = a^2 + b^2
c^2 = 3.4^2 + 2.6^2
c^2 = 11.56 + 6.76
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answer
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4 0
3 years ago
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The total number of? restaurant-purchased meals that the average person will eat in a? restaurant, in a? car, or at home in a ye
zmey [24]

Answer:

<em>The number of restaurant-purchased meals eaten in a restaurant is 75, the number eaten in a car is 33 and the number eaten at home is 55.</em>

Step-by-step explanation:

Suppose, the number of meals eaten in a restaurant is x , in a car is y and at home is z

The total number of meals eaten in a restaurant, in a car or at home is given as 163. So, the first equation will be......

x+y+z=163 .............................(1)

The total number meals eaten in a car or at home exceeds the number eaten in a restaurant by 13. So, the second equation will be......

y+z=x+13 ................................(2)

Twenty more restaurant-purchased meals will be eaten in a restaurant than at home. So, the third equation will be......

x= z+20..................................(3)

First, <u>substituting equation (2) into equation (1)</u>, we will get........

x+(x+13)=163\\ \\ \Rightarrow 2x+13=163\\ \\ \Rightarrow 2x=163-13=150\\ \\ \Rightarrow x=\frac{150}{2}=75

<em>Now plugging this x=75 into equation (3)</em>, we will get......

75=z+20\\ \\ \Rightarrow z=75-20= 55

<em>Plugging x=75 and z=55 into equation (1)</em> .........

75+y+55=163\\ \\ \Rightarrow y+130=163\\ \\ \Rightarrow y=163-130=33

So, the number of restaurant-purchased meals eaten in a restaurant is 75, the number eaten in a car is 33 and the number eaten at home is 55.

8 0
3 years ago
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