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3 years ago

) In a nuclear reaction, which quantity is the same before and after the change? (1 point)

Chemistry

1 answer:

olganol [36]3 years ago

8 0

Answer:

In alpha decay, shown in Fig. 3-3, the nucleus emits a 4He nucleus, an alpha particle. Alpha decay occurs most often in massive nuclei that have too large a proton to neutron ratio. An alpha particle, with its two protons and two neutrons, is a very stable configuration of particles. Alpha radiation reduces the ratio of protons to neutrons in the parent nucleus, bringing it to a more stable configuration. Many nuclei more massive than lead decay by this method.

Explanation:

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Help Pls!!

AlexFokin [52]

The mass of carbon in 1 liter of mixture = 1.108 g

<h3>What is the mass of carbon in 1 liter of the mixture?</h3>

The mass of carbon in 1 liter of the mixture is determined as follows:

First the moles of gas is determined using the ideal gas formula:

n = PV/RT

n = (1 * 1)/(0.08205L * 298)

n = 0.0409 mole of total gas

mass of gas is then determined using the formula:

mass = density * volume

mass = 1 * 1.375

mass = 1.375 g

Let x = mass of CH₄ and y = mass of C₄H₁₀

x + y = 1.375 g

nCH₄ + nC₄H₁₀ = ntotat

moles = mass/molar mass

x + y = 1.695 => y = 1.695 - x

(x/molar mass of CH₄) + [(1.375 - x)/ molar mass C₄H₁₀ = 0.0409

x/16 + (1.375 - x)/58 = 0.0409

x = 0.380 g CH₄

y = 1.375 - 0.380

y = 0.995 g of C₄H₁₀

mass of C in CH₄ = 12/16 * 0.380 = 0.285

mass of C in C₄H₁₀ = 48/58 * 0.995 = 0.823

Mass of carbon in 1 liter of mixture = 0.285 + 0.823

Mass of carbon in 1 liter of mixture = 1.108 g

In conclusion, the carbon is the major component in the mixture.

Learn more about ideal gas at: brainly.com/question/20348074

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6 0

2 years ago

What is the percent by mass (mv) of a solution with 1.56 g of benzene dissolved in gasoline to make 998.44 mL of solution? (dens

Marina CMI [18]

Answer:

The percentage by mass of benzene in the solution is approximately 0.2%

Explanation:

The given parameters are;

The mass of the benzene solute dissolved in the gasoline solvent, m₁ = 1.56 g

The total volume of the benzene gasoline solution made, V = 998.44 mL

The density of gasoline, ρ = 0.7489 g/mL

Mass, m = Density, ρ × Volume, V

∴ The mass of gasoline in the 998.44 mL, solution = 0.7489 g/mL × 998.44 mL = 747.731716 g

The total mass of the solution = The mass of the benzene in the solution + The mass of the gasoline in the solution

∴ The total mass of the solution = 747.731716 g + 1.5 g = 749.231716 g

$The \ percentage \ by \ mass = \dfrac{The \ mass \ of \ a \ fraction}{(The \ mass \ of \ the \ total \ solution)} \times 100$

The percentage by mass of benzene in the solution = (1.5 g/749.231716 g)×100 ≈ 0.2% by mass.

6 0

3 years ago

What is <br> 78.432 miles x 322.3 miles

Phoenix [80]

That would be 25,270.7904 miles

8 0

3 years ago

If the temperature of an ideal gas is raised from 100◦C to 200◦C, while the pressure remains constant, the volume 1. increases b

mel-nik [20]

Answer:

3. doubles

Explanation:

for an ideal gas behavior, the relationship between volume and temperature is given by Charles law

Charles law states that the volume of a given mass of gas is directly proportional to its temperature provided that pressure remains constant. Mathematically, this is represented as

V ∝ T

V=KT

K = V/T

where V is the volume of the gas

T is the Temperature

k represents the constant of proportionality

For initial and final conditions of a gas,

$\frac{V_{1} }{T_{1} }$ = $\frac{V_{2} }{T_{2} }$

where 1 and 2 represent initial and final conditions respectively

therefore, T₁ = 100 and T₂ = 200

$\frac{V_{1} }{100}$ = $\frac{V_{2} }{200}$

200 × V₁ = 100 × V₂

divide both sides by 100

2V₁ = V₂

final volume,V₂ = 2V₁

there the volume doubles

3 0

3 years ago

Sulfuric acid (H2SO4) is prepared commercially from elemental sulfur using the contact process. In a typical sequence of reactio

Elan Coil [88]

I believe the end result is still 83 moles since there is never an amount of sulfur atoms added to the initial amount, but rather oxygen and water is repeatedly added to it. To find it's weight, first find the molar mass of H2SO4:

H2 + S + O4 = 2.00 + 32.1 + 64.0 = 98.1 g/mol

and mass = (98.1 g/mol)(83 mol) = 8142.3 g

rounded to 8.1 x 10^3 g assuming 100% yield?

8 0

3 years ago

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