Answer:
Explanation:
We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.
We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.
Next, convert these masses to moles, using the molar masses found on the Periodic Table.
- P: 30.974 g/mol
- Cl: 35.45 g/mol
Use the molar masses as ratios and multiply by the number of grams. 
Divide both of the moles by the smallest number of moles to find the mole ratio.
The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as:<u> PCl₃</u>
Answer:
The Structure of "B" is alkene.
Explanation:
The compound "A" having R- configuration and undergoes Hofmann elimination to form an alkene.
The compound "B" on oxidatively cleaving with ozone followed by dimethyl sulfide forms 
and 
The structure of "A" and"B" is as follows.
Pyruvic acid is the end product of the Link reaction in respiration.
Hope that helps
There are two kinds of polymers : addition polymers and condensation polymers
In case of addition polymers, there is simple addition of unsaturated monomeric units. example: polythene
While in case of condensation polymers, the monomers combine with the elimination of a small molecule like H2O, HCl, NH3 etc.
So here as there is formation of H2O as product there is formation of a polymer and that too a condensation polymer
Example: condensation polymer of diamine and dicarboxylic acid to form a polyamide (Nylon-6,6)
Answer: condensation
formation of polymer
Answer:
B. They are stereoisomers
C. They are enantiomers
Explanation:
Let us consider all the options
A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)
B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.
C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions
D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case
E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid
