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Luden [163]
4 years ago
7

If a solid has a density of 4g/cm^3 what volume of the solid has a mass of 24g? show work

Chemistry
1 answer:
ki77a [65]4 years ago
6 0

Answer:

0.167cm^3

Explanation:

density=mass/volume

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Is C2H6 empirical molecular or both
marshall27 [118]

Answer:

molecular

Explanation:

7 0
3 years ago
Which of the following is a FALSE statement about carbohydrates? Glycogen is a complex carbohydrate formed by dehydration synthe
natka813 [3]

Answer:

The chemical composition of carbohydrates includes two oxygens and one hydrogen for every carbon present.

Explanation:

Generally, each carbon atom in the carbohydrates has one oxygen molecule and 1 – 3 hydrogen (depending on the position of the carbon in the chain and also the types of bonds around it). Usually, the ratio of hydrogen to oxygen in carbohydrates is approximately 2:1 Example of carbohydrates are starch and glycogen.

6 0
3 years ago
What is the limiting reactant ?
Sav [38]

The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it.
4 0
4 years ago
Yellow bone marrow is located within the medullary cavity and is rich in fats.
rosijanka [135]

Answer:

true

Explanation:

The second type of bone marrow found in the body is yellow bone marrow, which gets its name from its high concentration of fat cells, which appear yellow in color. This type of bone marrow can be found in the medullary cavity in the shaft of long bones and is often surrounded by a layer of red bone marrow.

8 0
3 years ago
Starting with a 6.847 M stock solution of HNO3, five standard solutions are prepared via serial dilution. At each stage, 25.00 m
stiks02 [169]

Answer: The concentration of HNO_3 in the final solution is 0.006688 M and number of moles are 0.00006688

Explanation:

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 6.847 M

V_1 = volume of stock  solution = 25.00 ml

M_2 = molarity of ist dilute solution = ?

V_2 = volume of first dilute solution = 100.0 ml

6.847\times 25.00=M_2\times 100.0

M_2=1.712M

2) on second dilution;

1.712\times 25.00=M_2\times 100.0

M_2=0.4280M

3) on third dilution

0.4280\times 25.00=M_2\times 100.0

M_2=0.1070M

4) on fourth dilution

0.1070\times 25.00=M_2\times 100.0

M_2=0.02675M

5) on fifth dilution

0.02675\times 25.00=M_2\times 100.0

M_2=0.006688M

Thus the concentration of HNO_3 in the final solution is 0.006688 M

moles of HNO_3 = Molarity\times {\text {Volume in L}}=0.006688\times 0.01L=0.00006688moles

5 0
4 years ago
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