Answer: 2.73g of CH3CH2OH Will be consumed
Explanation:
CH3CH2OH + O2 —> CH3COOH + H2O
MM of CH3CH2OH = 12 + 3 +12 + 2 16 +1 = 46g/mol
MM of O2 = 16 x2 = 32
Mass conc. Of O2 = 1.9g
From the equation,
32g of O2 consumed 46g of CH3CH2OH .
Therefore, 1.9g of O2 will consume Xg of CH3CH2OH i.e
Xg of CH3CH2OH = (1.9 x 46)/32 = 2.73g
The answer is the first option. Gas burning in an engine is an example of a chemical change. Chemical change is a change where the substance changes in identity or form new substances after undergoing a process. In this case, the gas reacts with oxygen forming combustion products, commonly carbon dioxide and water.
Answer:
energy goes into the chemical and cool downs the surrounding area.
40.0mL(1 L/1000 mL) = 0.040 L
<span>then plug into the formula M = moles/liters </span>
<span>0.035 M = moles/ 0.040L </span>
<span>multipy both sides by 0.040L, and you get 0.0014 moles </span>
<span>so the answer is 1</span>
Answer:
Reduction
Explanation:
The charge on Mg goes from 2+ to 0 which means this is a reduction.
