Explanation:
1) Initial mass of the Cesium-137=
= 180 mg
Mass of Cesium after time t = N
Formula used :
Half life of the cesium-137 = ![t_{1/2}=30 years[p/tex]where, [tex]N_o](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D30%20years%5Bp%2Ftex%5D%3C%2Fp%3E%3Cp%3Ewhere%2C%0A%3C%2Fp%3E%3Cp%3E%5Btex%5DN_o)
= initial mass of isotope
N = mass of the parent isotope left after the time, (t)
= half life of the isotope
= rate constant
Now put all the given values in this formula, we get
Mass that remains after t years.
Therefore, the parent isotope remain after one half life will be, 100 grams.
2)
t = 70 years
N = 35.73 mg
35.73 mg of cesium-137 will remain after 70 years.
3)
N = 1 mg
t = ?
t = 224.80 years ≈ 225 years
After 225 years only 1 mg of cesium-137 will remain.
Answer:
The answer is
<h2>16.8 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass of object = 52.9 g
density = 3.14 g/mL
The volume of the object is
We have the final answer as
<h3>16.8 mL</h3>
Hope this helps you
Answer:
1.18 moles of CS₂ are produced by the reaction.
Explanation:
We present the reaction:
5C + 2SO₂ → CS₂ + 4CO
5 moles of carbon react to 2 moles of sulfur dioxide in order to produce 1 mol of carbon disulfide and 4 moles of carbon monoxide.
As we do not have data from the SO₂, we assume this as the excess reagent. We convert the mass of carbon to moles:
70.8 g / 12 g/mol = 5.9 moles
Ratio is 5:1, so 5 moles of carbon react to produce 1 mol of CS₂
Then, 5.9 moles will produce (5.9 . 1) / 5 = 1.18 moles
Answer:
i) The bond angle decreases due to the presence of lone pairs, which causes more repulsion on the bond pairs and as a result, the bond pairs tend to come closer. ii) The repulsion between electron pairs increases with an increase in electronegativity of the central atom and hence the bond angle increases.
Explanation:
C plasmas have a net negative charge
