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likoan [24]
3 years ago
5

If the price of gasoline is $2.99 per U.S. gallon, what is the cost per liter? (1 L = 1.06 qt)

Chemistry
2 answers:
sasho [114]3 years ago
8 0

Answer:

About $0.79

Explanation:

There is about 3.78541 liters in 1 gallon. So, you would divide $2.99 by 3.78541 to make it the amount per liter. 2.99/3.78541= 0.78987481. That number rounded to the nearest cent is $0.79. Hope this helps! :)

AfilCa [17]3 years ago
5 0
Answr: it is 22

Explanation: i
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Law Incorporation [45]

Answer:

The transformation is of chemical energy (use the ATP molecule as a resource) which is then transformed into mechanical energy (muscle contraction) and finally transformed into thermal energy (increase in body temperature, or sweating)

Explanation:

Energy is never lost, it is always transformed, that is why energy is yielding electronic movement and expressing itself in different ways, first as chemical energy, then as mechanical energy, and lastly as thermal energy.

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3 years ago
When Barium chloride is formed, what questions will the student need to know prior to making the formula???
guapka [62]

Answer:

Valency of the two elements

Explanation:

In order to correctly formularize the compound, the student needs to ask of the valences of the elements involved.

Chlorine has valency of -1, while Barium +2.

The exchange of valency gives the formula BaCl_{2}.

Another explanation is that Barium donates 2 electrons which the chlorine atoms accept, in order to form the covalent bond.

I hope this was helpful.

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3 years ago
A fossil that looks like a spiral or a rams horns
anygoal [31]

Answer:

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6 0
3 years ago
Read 2 more answers
The standard molar enthalpy of formation of NH3(g) is -45.9 kJ/mol. What is the enthalpy change if 9.51 g N2(g) and 1.96 g H2(g)
Vladimir [108]

Answer:

\Delta H=-29.7kJ

Explanation:

Hello!

In this case, since the undergoing chemical reaction is:

N_2+3H_2\rightarrow 2NH_3

We first need to identify the limiting reactant given the masses of nitrogen and hydrogen:

n_{NH_3}^{by\ H_2}=1.96gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.647molNH_3\\\\  n_{NH_3}^{by\ N_2}=9.51gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.679molNH_3

It means that only 0.647 moles of ammonia are yielded, so the resulting enthalpy change is:

\Delta H=0.647molNH_3*\frac{-45.9kJ}{1molNH_3}\\\\ \Delta H=-29.7kJ

Best regards!

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3 years ago
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