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2 years ago

can energy and matter be created during photosynthesis and cellular respiration pleasssseeee this is due today

Chemistry

2 answers:

Murljashka [212]2 years ago

5 0

Answer:

No.

Energy cannot be created nor destroyed, it changes form.

Explanation:

Energy is collected by eukaryotes through chloroplasts which is converted to glucose and goes through ATP.

barxatty [35]2 years ago

4 0

Answer:

We can see that the energy and mass are transformed in other forms via cellular respiration and photosynthesis. Plants breathe carbon dioxide and expel oxygen.

Explanation:

Photosynthesis is where a plant takes light from the sun, water from the soil, and carbon dioxide from the air, and turns it into two things: glucose, which it uses for energy, and oxygen, which it releases into the air. ... Matter and energy is neither created nor destroyed, so it all has to go somewhere

hehe

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What is the rate constant of a reaction if rate = 0.2 (mol/L)/s, [A] and [B] are each 3 M, m = 1, and n = 2?

tino4ka555 [31]

M= 1 and n = 2
( m+ n = 1 +2 = 3)

rate = K [A] [B]^2

0.2 = K * 3 * 3 ^2
0.2 = K * 3 * 9
K = 0.2 / 27
K = 7.408 * 10 ^ -3 m^-2 s^-1

4 0

3 years ago

Read 2 more answers

2Ag + H2S ➞ Ag2S + H2

NeX [460]

Answer:

The correct answer is <em>C) Two atoms of silver are needed to complete the reaction.</em>

Explanation:

The Law of Conservation of Matter postulates that "the mass is not created or destroyed, only transformed." This means that the reagents interact with each other and form new products with physical and chemical properties different from those of the reagents because the atoms of the substances are ordered differently. But the amount of matter or mass before and after a transformation (chemical reaction) is always the same, that is, the quantities of the masses involved in a given reaction must be constant at all times, not changing in their proportions when the reaction ends.

Then, taking into account the Law of Conservation of Matter, as an atom cannot be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

For this, the chemical equation must be balanced. For that, you must first look at the subscripts next to each atom to find the number of atoms in each compound in the equation. If the same atom appears in more than one molecule, you must add its quantities. On the other hand, the coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts. By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

In this case:

Left side: 2 silver (Ag), 2 hydrogen (H) and 1 sulfur (S)

Right side: 2 silver (Ag), 2 hydrogen (H) and 1 sulfur (S)

In this case the equation is balanced because you have the same amount of all the elements on each side of the reaction. And <u><em>the 2 in front of 2Ag indicates that,since silver is a reagent, two atoms of silver are needed to complete the reaction. (option C).</em></u>

4 0

3 years ago

Read 2 more answers

Problem Page What kind of intermolecular forces act between a formaldehyde molecule and a hydrogen sulfide molecule? Note: If th

malfutka [58]

Answer:

Hydrogen Bonding

Explanation:

Formaldehyde, H2CO, has an oxygen atom which is quite electronegative that means it would attract any atom with a slightly positive charge. Hydrogen in the Hydrogen sulfide (H2S) is attracted by oxygen and hence hydrogen bonding can occur.

8 0

2 years ago

Please help!!! (im really bad at chemistry)

Lubov Fominskaja [6]

Answer:

1000ml/1L

Explanation:

8 0

2 years ago

C. Use Hess's law and the following equations to calculate ΔH for the reaction 4NH3 (g) + 5O2 (g) 4NO(g) + 6H2 O(g). Show your w

Monica [59]

Considering the Hess's Law, the enthalpy change for the reaction is -906.4 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: 2 N₂ + 6 H₂ → 4 NH₃ ΔH = –183.6 kJ/mol

Equation 2: 2 N₂ + 2 O₂ → 4 NO ΔH = 361.1 kJ/mol

Equation 3: 2 H₂ + O₂→ 2 H₂O ΔH = -483.7 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 4 moles of NH₃ on reactant side and it is present in first equation on product side. So you need to invert the reaction, and when an equation is inverted, the sign of delta H also changes.

Now, 4 moles of NO must be a product and is present in the second equation, so let's write this as such.

Finally, you need 6 moles of H₂O on the product side, so you need to multiply by 3 the third equation to obtain the amount of water that you need. Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 3, the variation of enthalpy also.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 4 NH₃ → N₂ + 6 H₂ ΔH = 183.6 kJ/mol

Equation 2: 2 N₂ + 2 O₂ → 4 NO ΔH = 361.1 kJ/mol

Equation 3: 6 H₂ + 3 O₂→ 6 H₂O ΔH = -1,451.1 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O ΔH= -906.4 kJ/mol

Finally, the enthalpy change for the reaction is -906.4 kJ/mol.

Learn more about Hess's law:

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