Answer: Ions may be defined as the element that contains either positive or negative charge over them. Two types of ions are cations and anions. The outermost electrons are involved in the formation of ions.
The atomic number of sulfur is 16. Its outermost electronic configuration is K=2, L= 8, M= 6. The sulfur requres two more electrons to complete its orbit and accquire -2 charge.
Explanation:
Answer:
Yes, given statement is true.
Explanation:
Given that a cylinder of 1000 ml is marked at every 100 ml.
During the test, the student can easily check the volume of liquid so the student's guess is 750 ml true.
With this measurement, we can estimate that 1/10th of 100 ml can be measured.
So, given statement is correct.
Answer: -
Lower the specific heat capacity of the metal, more the amount of heat would be required to raise the temperature to the same extent.
So for the same amount of heat added to 5.00 g samples of metals, the metal with the lowest specific heat capacity would experience the smallest temperature change.
For example, if the elements are Al, Au ,Cu and Fe, then Au would experience the smallest temperature change due to least specific heat capacity.
Answer:
Lithium loses one electron to fluorine and forms ionic bond, having formula 
.
Explanation:
Lithium is the element of the group 1 and period 2 which means that the valence electronic configuration is ![[He]2s^1](https://tex.z-dn.net/?f=%5BHe%5D2s%5E1)
.
Fluorine is the element of the group 17 and period 2 which means that the valence electronic configuration is ![[He]2s^22p^5](https://tex.z-dn.net/?f=%5BHe%5D2s%5E22p%5E5)
.
<u>Thus, lithium loses 1 electron and become positively charged. Fluorine on the other hand accepts this electron and become negatively charged.</u> This is done in order that the octet of the atoms are complete. <u>These both ions then form ionic bond as their will be electrostatic interaction between the two oppositely charged ions.</u>
Thus, the formula of calcium chloride is .
Answer:
14.7°C
Explanation:
Q = m·ΔT·c
ΔT = 
ΔT =
= 1320 J / ((230 g) * (.39 J/g°C)
ΔT = 14.7 °C
