<span>The process of removing or adding electrons is called ionization </span>
I: Current
V: Voltage
R: resistance
you’re welcome ;)
When PH + POH = 14
∴ POH = 14 -7 = 7
when POH = -㏒[OH-]
7 = -㏒ [OH-]
∴[OH-] = 10^-7
by using ICE table:
Mn(OH)2(s) ⇄ Mn2+ (aq) + 2OH-(aq)
initial 0 10^-7
change +X +2X
Equ X (10^-7 + 2X)
when Ksp = [Mn2+][OH-]^2
when Ksp of Mn(OH)2 = 4.6 x 10^-14
by substitution:
4.6 x 10^-14 = X*(10^-7+2X)^2 by solving this equation for X
∴ X =2.3 x 10-5 M
∴ The solubility of Mn(OH)2 in grams per liter (when the molar mass of Mn(OH)2 = 88.953 g/mol
= 2.3 x10^-5 moles/L * 88.953 g/mol
= 0.002 g/ L
Phosphorus - P - Protons = 15, Electrons = 15, Neutrons = 16 - Non-Metal
Lithium - Li - Protons = 3, Electrons = 3, Neutrons = 4 - Metal
Nitrogen - N - Protons = 7, Electrons = 7, Neutrons = 7 - Non-Metal
Copper - Cu - Protons = 29, Electrons = 29, Neutrons = 34 - Metal
Neon - Ne - Protons = 10, Electrons = 10, Neutrons = 10 - Non-Metal
sorry i don’t know about the other questions but i thought i could help with the table!
Additional Info:
number of protons = atomic number
number of electrons = atomic number
number of neutrons = mass number - atomic number
