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bixtya [17]
2 years ago
5

According to valence bond theory, which orbitals overlap in the formation of the bond in hcl?

Chemistry
2 answers:
gulaghasi [49]2 years ago
8 0
According  to  valence  bond  theory    sigma  bonds   is  formed when   two  orbitals  approach  and overlap  over  each  other   while     pie  bonds  is  formed  when   two  orbitals  overlap  side  by  side. in formation  of    HCl   1s  orbital  of  hydrogen  overlap  on   3p  orbitals  of  chlorine
Juli2301 [7.4K]2 years ago
3 0

The overlap of s and p Z orbitals of H and Cl, respectively leads to the formation of the covalent bond in HCl.

Explanation

According to valence bond theory, the elements combine to form a compound by overlapping of orbitals with half filled electrons in it.

The valence bond theory is mostly suitable for compounds formed by covalent bonding as the valence bond theory assumes the overlapping or sharing of half filled electrons in the outermost shell.

In HCl, the electronic configuration of H is 1s1 while the electronic configuration of Cl is [Ne] 3s23p5.

So the outermost shell or the valence shell of the elements H and Cl contains 1 and 7 number of electrons.

So the 1 electron in the H will be shared with the 1 unpaired electron in the p orbital of the Cl element so that both H and Cl will be stabilized.  

It is known that p orbital will orient in px,py and pz orbitals.

So the 5 electrons in the p orbital of Cl will be divided as 2 electrons in px sub-orbital, 2 electrons in py sub-orbital and remaining 1 unpaired electron will be occupied in pz sub-orbital.

The arrangement of electrons in the p subshell is done with respect to Pauli's exclusion principle and Aufbau principle.

Thus the unpaired electron of hydrogen when is in s shell will overlap with the unpaired electron in pz sub-orbital of chlorine to form HCl compound.

So the overlap of spz orbitals lead to formation of HCl compound.

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Answer:

The answer is D.

Explanation:

Intermolecular force are negligible

When the distance between molecules decrease,

the attraction or repulsion become greater

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2 years ago
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6 0
3 years ago
Octane has a density of 0.692 g/ml at 20∘c. how many grams of o2 are required to burn 17.0 gal of c8h18
german

156251.099 grams of O₂ are required to burn 17.0 gal of C₈H₁₈

<h3>Further explanation</h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g / cm³ or kg / m³

Density formula:

\large{\boxed{\bold{\rho~=~\frac{m}{V} }}}

ρ = density

m = mass

v = volume

1 gal equal to = 3785.41 ml

then 17.0 gal = 17 x 3785.41 = 64351.97 ml Octane

grams Octane = ρ x ml

grams Octane = 0.692 g.ml x 64351.97

grams Octane = 44531.563

molar mass Octane (C₈H₁₈) = 114

mole Octane = grams : molar mass

mole Octane = 44531.563  : 114

mole Octane = 390.627

From the reaction

C₈H₁₈ + 25/2 O₂ ⇒ 8 CO₂ + 9H₂O

mole C₈H₁₈ : mole O₂ = 1 : 25/2

mole\:O_2\:=\:\frac{25}{2} \times\:390.627

mole O₂ = 4882.846

grams O₂ = mole x molar mass

grams O₂ = 4882.846 x 32

grams O₂ = 156251.099

<h3>Learn more </h3>

moles of water

brainly.com/question/1405182

grams of oxygen required

brainly.com/question/8175791

mass of copper required

brainly.com/question/1680090

Keywords: Octane,  mole, mass, gal, density

5 0
2 years ago
Which of the following equations can be used to determine the change in enthalpy of a system? A. `DeltaH_"reaction"=DeltaH_"prod
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<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]

Hence, the correct answer is Option D.

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3 years ago
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