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bixtya [17]
3 years ago
5

According to valence bond theory, which orbitals overlap in the formation of the bond in hcl?

Chemistry
2 answers:
gulaghasi [49]3 years ago
8 0
According  to  valence  bond  theory    sigma  bonds   is  formed when   two  orbitals  approach  and overlap  over  each  other   while     pie  bonds  is  formed  when   two  orbitals  overlap  side  by  side. in formation  of    HCl   1s  orbital  of  hydrogen  overlap  on   3p  orbitals  of  chlorine
Juli2301 [7.4K]3 years ago
3 0

The overlap of s and p Z orbitals of H and Cl, respectively leads to the formation of the covalent bond in HCl.

Explanation

According to valence bond theory, the elements combine to form a compound by overlapping of orbitals with half filled electrons in it.

The valence bond theory is mostly suitable for compounds formed by covalent bonding as the valence bond theory assumes the overlapping or sharing of half filled electrons in the outermost shell.

In HCl, the electronic configuration of H is 1s1 while the electronic configuration of Cl is [Ne] 3s23p5.

So the outermost shell or the valence shell of the elements H and Cl contains 1 and 7 number of electrons.

So the 1 electron in the H will be shared with the 1 unpaired electron in the p orbital of the Cl element so that both H and Cl will be stabilized.  

It is known that p orbital will orient in px,py and pz orbitals.

So the 5 electrons in the p orbital of Cl will be divided as 2 electrons in px sub-orbital, 2 electrons in py sub-orbital and remaining 1 unpaired electron will be occupied in pz sub-orbital.

The arrangement of electrons in the p subshell is done with respect to Pauli's exclusion principle and Aufbau principle.

Thus the unpaired electron of hydrogen when is in s shell will overlap with the unpaired electron in pz sub-orbital of chlorine to form HCl compound.

So the overlap of spz orbitals lead to formation of HCl compound.

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In chemistry, catenation is the bonding of atoms of the same element into a series, called a chain. A chain or a ring shape may be open if its ends are not bonded to each other, or closed if they are bonded in a ring

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A sample of carbon dioxide occupies a 5.13 dm3 container at STP. What is the volume of the gas at a pressure of 286.5 kPa and a
suter [353]

Considering the ideal gas law and STP conditions, the volume of the gas at a pressure of 286.5 kPa and a temperature of 12.9°C is 1.8987 L.

<h3>Definition of STP condition</h3>

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

<h3>Ideal gas law</h3>

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

  • P is the gas pressure.
  • V is the volume that occupies.
  • T is its temperature.
  • R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
  • n is the number of moles of the gas.  

<h3>Volume of gas</h3>

In first place, you can apply the following rule of three: if by definition of STP conditions 22.4 L are occupied by 1 mole of carbon dioxide, 5.13 L (5.13 dm³= 5.13 L, being 1 dm³= 1 L) are occupied by how many moles of carbon dioxide?

amount of moles of carbon dioxide=\frac{5.13 Lx1 mole of carbon dioxide}{22.4 L}

<u><em>amount of moles of carbon dioxide= 0.229 moles</em></u>

Then, you know:

  • P= 286.5 kPa= 2.8275352 atm (being 1 kPa= 0.00986923 atm)
  • V= ?
  • T= 12.9 C= 285.9 K (being 0°C= 273 K)
  • R= 0.082 \frac{atmL}{mol K}
  • n= 0.229 moles

Replacing in the ideal gas law:

2.8275352 atm× V = 0.229 moles×0.082 \frac{atmL}{mol K} × 285.9 K

Solving:

V= (0.229 moles×0.082 \frac{atmL}{mol K} × 285.9 K)÷ 2.8275352 atm

<u><em>V= 1.8987 L</em></u>

Finally, the volume of the gas at a pressure of 286.5 kPa and a temperature of 12.9°C is 1.8987 L.

Learn more about

STP conditions:

brainly.com/question/26364483

brainly.com/question/8846039

brainly.com/question/1186356

the ideal gas law:

brainly.com/question/4147359

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Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here: 750 J electrical energy is
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B) It was transformed into 350 J of heat energy.

Explanation:

The remaining 350J of energy must have been transformed into 350J of heat energy.

A fan works by converting electrical energy into heat energy.

  • According to the third law of thermodynamics "no system is 100% efficient". The conversion of the energy from one form to another involves a lost in energy.
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Answer: The correct option is A.

Explanation: The given molecules are the molecules of same element.

These molecules are considered as diatomic species.

Polar molecules are the molecules in which some polarity is present in the bond. These molecules are formed when there is some difference in the electronegativities of the elements. Example: HCl

Non-polar molecules are the molecules where no polarity is present in the bond. These molecules are formed when there is no difference in the electronegativities of the elements. Example: H_2, O_2

The given molecules are non-polar in nature.

Hence, these molecules must be non-polar. So, the correct option is A.

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