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bixtya [17]
3 years ago
5

According to valence bond theory, which orbitals overlap in the formation of the bond in hcl?

Chemistry
2 answers:
gulaghasi [49]3 years ago
8 0
According  to  valence  bond  theory    sigma  bonds   is  formed when   two  orbitals  approach  and overlap  over  each  other   while     pie  bonds  is  formed  when   two  orbitals  overlap  side  by  side. in formation  of    HCl   1s  orbital  of  hydrogen  overlap  on   3p  orbitals  of  chlorine
Juli2301 [7.4K]3 years ago
3 0

The overlap of s and p Z orbitals of H and Cl, respectively leads to the formation of the covalent bond in HCl.

Explanation

According to valence bond theory, the elements combine to form a compound by overlapping of orbitals with half filled electrons in it.

The valence bond theory is mostly suitable for compounds formed by covalent bonding as the valence bond theory assumes the overlapping or sharing of half filled electrons in the outermost shell.

In HCl, the electronic configuration of H is 1s1 while the electronic configuration of Cl is [Ne] 3s23p5.

So the outermost shell or the valence shell of the elements H and Cl contains 1 and 7 number of electrons.

So the 1 electron in the H will be shared with the 1 unpaired electron in the p orbital of the Cl element so that both H and Cl will be stabilized.  

It is known that p orbital will orient in px,py and pz orbitals.

So the 5 electrons in the p orbital of Cl will be divided as 2 electrons in px sub-orbital, 2 electrons in py sub-orbital and remaining 1 unpaired electron will be occupied in pz sub-orbital.

The arrangement of electrons in the p subshell is done with respect to Pauli's exclusion principle and Aufbau principle.

Thus the unpaired electron of hydrogen when is in s shell will overlap with the unpaired electron in pz sub-orbital of chlorine to form HCl compound.

So the overlap of spz orbitals lead to formation of HCl compound.

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The freezing point depression is calculated through the equation,
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where ΔT is the difference in temperature, kf is the freezing point depression constant (1.86°C/m), and m is the molality. Substituting the known values,
                                   5.88 = (1.86)(m)
m is equal to 3.16m

Recall that molality is calculated through the equation,
                                  molality = number of mols / kg of solvent
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3 years ago
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balu736 [363]

Answer:

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Explanation:

Hello!

In this case, we need to keep in mind that exothermic reactions release heat, so they increase the temperature as the final energy is less than the initial energy; in contrast, endothermic reactions absorb heat, so they decrease the temperature as the final energy is greater than the initial energy.

In such a way, when a dissolution process shows off a negative enthalpy of dissolution, we infer it is an exothermic process due to the aforementioned; therefore, the answer is:

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it can be said that

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