Explanation:
Let us assume that the concentration of [
and 
is equal to x. Then expression for 
for the given reaction is as follows.
![K_{w} = [OH^{-}][H^{+}]](https://tex.z-dn.net/?f=K_%7Bw%7D%20%3D%20%5BOH%5E%7B-%7D%5D%5BH%5E%7B%2B%7D%5D)
Now, we will take square root on both the sides as follows.
![[H^{+}] = 8.2 \times 10^{-8}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%208.2%20%5Ctimes%2010%5E%7B-8%7D)
M
Thus, we can conclude that the 
concentration in neutral water at this temperature is 
M.
Answer:
A. Boyle's Law
B. Charles' Law
C. Gay-Lussac's Law
Explanation:
An air bag inflates due to the decomposition of sodium azide or NaN₃ to completely fill the bag with nitrogen gas which is an example of Boyle's law, which states that the pressure of a given mass of gas is inversely proportional to its volume, hence due to the estricted volume of the airbag, the pressure of the nitrogen gas in the bag increses protecting the occupants of a cr from injuries in a crash
Helium balloon decrease in sice in a freezer is an example of Charlles law which states that the volume of a given mass of gas is nverslely proportionl to its temperature at constant pressure
A can of spray paint will explode if tossed into a fire is an example of Gay-Lussac's Law which states that the pressure of a given mass of gas is directly proportional to its temperature hence the increased pressure causes the can ti explode
Answer: -112200J
Explanation:
The amount of heat (Q) released from an heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = ?
Mass of water vapour = 30.0g
C = 187 J/ G°C
Φ = (Final temperature - Initial temperature)
= 100°C - 120°C = -20°C
Then apply the formula, Q = MCΦ
Q = 30.0g x 187 J/ G°C x -20°C
Q = -112200J (The negative sign does indicates that heat was released to the surroundings)
Thus, -112200 joules of heat is released when cooling the superheated vapour.
Answer:
they are inversly related
Explanation:
As the force increases distance decreases .They are related with an equation
F= Gm1×m2/r^2
The molarity of a solution is found to be 10 M.
Explanation:
- Molarity of a solution = <u>moles solute</u>
Litres solution
5
- Molarity of a solution = 10 M
