The largest group of organisms that is capable of interbreeding is Species.
Answer:
160 g of NaOH
Explanation:
Reaction: 2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O
When a base and an acid react, the produce water and a salt. → Neutralization
In this reaction 2 moles of hydroxide need 1 mol of sulfuric acid to react, it is the same to say that 1 mol of sulfuric acid needs 2 moles of NaOH to react. We convert the mass of sulfuric to moles and we propose the rule of three:
196 g / 98 g/mol = 2 moles
1 mol of sulfuric acid needs 2 moles of NaOH to react
Then 2 moles of sulfuric acid will react with (2 . 2) /1 = 4 moles of NaOH
We convert the moles of base to grams → 4 mol . 40 g /1mol = 160 g
Answer:
Six electrons are transferred in the formation of Al₂O₃.
Explanation:
Aluminium metal and Oxygen react to form Al₂O₃ as,
2 Al + 3/2 O₂ → Al₂O₃
Oxidation number of Al on left hand side is zero, while than on right hand side in Al₂O₃ is +3. Means it has lost 3 electrons per one atom and six electrons per two atoms. Also, the oxidation number of O at left hand side in O₂ is zero, while that in Al₂O₃ it is -2 per atom and -6 per 3 atoms.
So, two Al atoms have lost 6 electrons and 3 O atoms have gained six electrons.
Answer:
6 atoms
Explanation:
In 6 moles of HCL (hydrochloric acid), there are 6 hydrogen atoms. Think about it this way: there is one hydrogen atom in HCL, or one hydrogen atom in one mole of HCL. Since there are 6 moles of HCL instead of one, this means there are six times as many hydrogen atoms. 6 times 1 is 6.
Answer:
1. 75.82 m^3 (cubic meters)
2. 75820 L (Liters)
Explanation:
Given data
L = 21 FT
W = 17 ft
h = 7 ft 6 in
Calculation
Formula to calculate volume is:
V= L×W×h
put the values in formula
V = 21 ft × 17 ft × 7 ft 6 in
V = 2677.5 ft
Now we will convert Cubic ft to cubic meters, as we know that 1 cubic meter is equal to 35.3147 cubic feet
V (m^3) = 2677.5 ÷ 35.3147
V (m^3) = 75.82 m^3
Now we will calculate liters
as we know that 1 cubic meter is equal to 1000 liters
so multiply the ans. with 1000
L = 75.82 × 1000
L = 75820 l
