The apple is lifted by 1.1 m
<u>Explanation</u>:
- Given that, mgh = 2 J and mass of apple = 180g
- Step 1: convert grams to kg as work is given in SI units.
180 g = 0.18 kg
- Step 2: substitute in the formula for work done.
0.18 * 10 * h = 2
- Step 3: calculate the value of h from this formula.
h = 2/1.8
h = 1.11 m
Answer:
Explanation:
a) Using the equation of motion
S = ut + 1/2gt²
S is the distance of fall
g is the acceleration due to gravity
t is the time taken
Given S = 12.0m, g = 9.81m/s^2, un= 0m/s
12 = 0+1/2(9.81)t²
12 = 4.905t²²²
t² = 12/4.905
t² = 2.446
t = √2.446
t = 1.56secs
b) To determine how fast is the frog falling at this point, we need to calculate the speed of the frog. Using the equaton v = u+gt
v = 0+9.81(1.56)
v = 15.34m/s
Hence the frog is falling at the rate of 15.34m/s
Answer:
this was 2 weeks ago, but im pretty sure the correct answers are:
B=c
C=d
D=b
hope this helps and is correct :)
Answer:
Because sound doesn't move in vacuum (of space)
Answer:
4.68227 °C
Explanation:
= Mass of object = 500 kg
= Mass of water = 25 kg
c = Specific heat of water at 20°C = 4186 J/kg°C
h = Height from which the object falls = 100 m
g = Acceleration due to gravity = 9.8 m/s²
The potential energy and heat will balance each other
The temperature change in the water is 4.68227 °C
