All categories

2 years ago

An impulse of 12.2kg m/s is delivered to an object whose initial momentum is 4.5kgm/s. What is the object's final momentum?

Physics

1 answer:

AleksandrR [38]2 years ago

5 0

Answer:

Object's final momentum = 16.7 kg-m/s

Explanation:

Given that,

Impulse, J = 12.2 kg-m/s

Initial momentum, $P_i=4.5\ kg-m/s$

We need to find the object's final momentum. We know that the impulse is equal to the change in momentum. So,

Impulse = change in momentum

$J=P_f-P_i\\\\P_f=J+P_i\\\\P_f=12.2+4.5\\\\P_f=16.7\ kg-m/s$

So, the object's final momentum is 16.7 kg-m/s.

You might be interested in

What effect does a catalyst have on a system in equilibrium?

Jet001 [13]

ANSWER:

What effect does a catalyst have on a system in equilibrium?

The system is unaffected.

~batmans wife dun dun dun....

8 0

3 years ago

2. Which of the following is not used to calculate kinetic energy?

Komok [63]

Answer:

speed cannot be used to calculate the temperature

4 0

3 years ago

Read 2 more answers

A circular flat coil that has N turns, encloses an area A, and carries a current i, has its central axis parallel to a uniform m

gogolik [260]

Answer:

A. Zero

Explanation:

The force on a coil of N turns, enclosing an area, A and carrying a current I in the presence of a magnetic field B, is :

F = N * I * A * B * sinθ

Where θ is the angle between the normal of the enclosed area and the magnetic field.

Since the normal of the area is parallel to the magnetic field, θ = 0

Hence:

F = NIABsin0

F = 0 or Zero

3 0

2 years ago

A car is going south on I-69 at 33 m/s (74 mph). The car has good brakes so its maximum braking acceleration is – 8.5 m/s^2 . Tr

dmitriy555 [2]

Answer:

1.69515 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-33^2}{2\times -8.5}\\\Rightarrow s=64.06\ m$

The distance between the traffic and the car after braking is 120-64.06 = 55.94 m

Time = Distance / Speed

$\text{Time}=\frac{55.94}{33}\\\Rightarrow \text{Time}=1.69515\ seconds$

The reaction time cannot be more than 1.69515 seconds

4 0

3 years ago

What phase difference between two otherwise identical harmonic waves, moving in the same direction along a stretched string, wil

lora16 [44]

Answer:

$\theta=145$

Explanation:

The amplitude of he combined wave is:

$B=2Acos(\theta/2)\\$

A, is the amplitude from the identical harmonic waves

B, is the amplitude of the resultant wave

θ, is the phase, between the waves

The amplitude of the combined wave must be 0.6A:

$0.6A=2Acos(\theta/2)\\ cos(\theta/2)=0.3\\\theta/2=72.5\\\theta=145$

5 0

3 years ago