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Alinara [238K]
2 years ago
13

RIDDLE

Physics
1 answer:
xenn [34]2 years ago
3 0

Answer :First Man

<h2>E<em>xplanation :He went to the first one bc he knew nobody would be there so he could kill him and nobody will notice bc there at the first man shop</em></h2><h2><em></em></h2>
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A ball is thrown upward with an initial velocity of +9.8 m/s. How high does it reach before it starts descending?
aksik [14]
Hope this helps you.

3 0
3 years ago
Waves diffract the most when their wavelength is
djverab [1.8K]
<h2>Answer: about the same size of the gap  or slit</h2>

Diffraction happens when a wave (mechanical or electromagnetic wave, in fact, any wave) meets an obstacle or a slit .When this occurs, the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit.

Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.

In other words, when the gap (or slit) size is larger than the wavelength, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs.

Therefore:

<h2>Waves diffract the most when their wavelength is <u>about the same size of the gap </u></h2>

<u />

5 0
2 years ago
What is the derivative of x^2 - x + 3 at the point x = 5?​
Hunter-Best [27]

Answer:

9

Explanation:

d/dx (x² - x + 3)

= 2x - 1

when x = 5,

2x-1

= 2(5) - 1

= 10 - 1

= 9

5 0
2 years ago
Please help me i need help only way i’ll pass
pickupchik [31]

Answer:

they require a medium

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your welcome.............

3 0
2 years ago
As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p
Irina-Kira [14]

Answer:

The magnitude of each force is 2.45 x 10⁻¹⁶ N

Explanation:

The charge of proton, +q = 1.603 x 10⁻¹⁹ C

The charge of electron, -q = 1.603 x 10⁻¹⁹ C

Distance between the two charges, r = 971 nm = 971 x 10⁻⁹ m

Apply Coulomb's law;

F = \frac{kq_1q_2}{r^2}

where;

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

q₁ and q₂ are the charges of proton and electron respectively

F is the magnitude of force between them

Substitute in the given values and solve for F

F = \frac{(8.99*10^9)(1.603*10^{-19})^2}{(971*10^{-9})^2} \\\\F = 2.45*10^{-16} \ N

Therefore, the magnitude of each force is 2.45 x 10⁻¹⁶ N

4 0
2 years ago
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