All categories

3 years ago

Zero, zero, zero, zero, zero, one, one, one, one, one, one, one, one, two, two, three, four, four, four, twenty one,

Mathematics

1 answer:

Natasha2012 [34]3 years ago

6 0

Answer:

Yes , They would.

Step-by-step explanation:

value that "lies outside" (is much smaller or larger than) most of the other values in a set of data . Each if the numbers would be an outlier applying to the rule / function.

You might be interested in

Please help me with these two questions, i will give brainliest

valentinak56 [21]

Answer:

5. No, Triangle J K L is a Reflection, not a translation

6. Its 11 to the right, and 2 up

8 0

3 years ago

Read 2 more answers

Helpppppppp fastttttttttt

soldi70 [24.7K]

Answer:

the answer is all of the stores( store A, B, C, D)

Step-by-step explanation:

$8.43 divided by 3 is 2.81 per pound

$9.51 divided by 3 is 3.17 per pound

$2.58 divided by 3 is 0.86 per pound

$5.19 divided by 3 is 1.73 per pound

and 3.49>3.17>2.81>1.73>0.86

4 0

3 years ago

Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit repr

NNADVOKAT [17]

Answer:

C. 26 yards

Step-by-step explanation:

Jamie's fence total length = perimeter of the polygon

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

AB, FA and DE can be worked accordingly as shown below:

AB = |-5 - 0| = 5 units

FA = |5 - 2| = 3 units

DE = |1 -(-2)| = 3 units

BC, CD, and EF can be calculated using the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Distance between B(0, 5) and C(4, 2):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(0, 5) = (x_1, y_1)$

$C(4, 2) = (x_2, y_2)$

$BC = \sqrt{(4 - 0)^2 + (2 - 5)^2}$

$BC = \sqrt{(4)^2 + (-3)^2}$

$BC = \sqrt{16 + 9} = \sqrt{25}$

$BC = 5 units$

Distance between C(4, 2) and D(1, -2)

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(4, 2) = (x_1, y_1)$

$D(1, -2) = (x_2, y_2)$

$CD = \sqrt{(1 - 4)^2 + (-2 - 2)^2}$

$CD = \sqrt{(-3)^2 + (-4)^2}$

$CD = \sqrt{9 + 16} = \sqrt{25}$

$CD = 5 units$

Distance between E(-2, -2) and F(-5, 2):

$EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$E(-2, -2) = (x_1, y_1)$

$F(-5, 2) = (x_2, y_2)$

$EF = \sqrt{(-5 -(-2))^2 + (2 -(-2))^2}$

$EF = \sqrt{(-3)^2 + (4)^2}$

$EF = \sqrt{9 + 16} = \sqrt{25}$

$EF = 5 units$

Total length of the wall in yards = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

4 0

3 years ago

THIS ONE IF FOR YOU hdomingu0023!<br> (Random) What is (2x9)+708-888+1231=

Irina-Kira [14]

Answer:

lol im not that person but i will still do it

Step-by-step explanation:

2x9=18

18+708=

726-888=

-162+1231=

1069

well ig the answer is 1069

8 0

3 years ago

PLEASE HELP ME I NEED HELP PLEASE HELP

lyudmila [28]

Answer:

1st question is 1:2

2nd question is 5

Step-by-step explanation:

15 times two is 30, so if you divide both 15 and 30 by 15, you get 1:2

Divide 300 and 60 and you get 5.

6 0

3 years ago

Read 2 more answers