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3 years ago

A triangle has an area of 15. One of its sides has length 10. What is the length of the altitude to that side?

Mathematics

2 answers:

Masteriza [31]3 years ago

6 0

The answer is 75 lmk how it goes

UNO [17]3 years ago

4 0

Answer:

Im to lazy to calculate the entire answer but its basically the formula is a*b/2

Step-by-step explanation:

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Right angle trigonometry

Nady [450]

Answer:

Step-by-step explanation:

Given

sinΘ = $\frac{1}{\sqrt{2} }$ , then

Θ = $sin^{-1}$ ( $\frac{1}{\sqrt{2} }$ ) = 45° → B

7 0

3 years ago

HELP!! I only need the answer. Thank you!

zvonat [6]

The answer would be 6 3/8

Hope this helps c:

5 0

3 years ago

I need help w this, thanks

Rama09 [41]

60 I believe I hope this helps if it was right :)

3 0

3 years ago

Read 2 more answers

Describe and correct the error in finding csc θ, given that θ is an acute angle of a right triangle and cos θ =7/11

a_sh-v [17]

Answer:

<h2>cosecθ = 1/sinθ = 11/6√2</h2>

Step-by-step explanation:

Given that cos θ =7/11, cosec θ = 1/sinθ in trigonometry.

Based on SOH, CAH, TOA;

cosθ = adjacent/hypotenuse = 7/11

adjacent = 7 and hyp = 11

Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.

Using pythagoras theorem to get the opposite;

$hyp^{2} = adj^{2} + opp ^{2} \\opp = \sqrt{hyp^{2} - adj^{2} } \\opp = \sqrt{11^{2} - 7^{2}} \\opp = \sqrt{72} \\opp = 6\sqrt{2}$

sinθ = 6√2/11

cosecθ = 1/sinθ = 1/( 6√2/11)

cosecθ = 1/sinθ = 11/6√2

Note the error; cscθ $\neq$ 1/cosθ but cscθ = 1/sinθ

6 0

3 years ago

I am a multiple of 10.my factors incluide an even number and an odd number. i am greater than 3x5 and less,than 4x7. what number

Alex17521 [72]

3×15=15
4×7=28
The only multiple of 10 between these two numbers is 20. 20 does indeed have factors that are odd or even so we can conclude that 20 must be the answer.

6 0

3 years ago