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Julli [10]
2 years ago
5

A uniform 40-N board supports two children weighing 500 N and 350 N. If the support is at the center of the board and the 500-N

child is 1.5 m from its center, How far is the 350-N child from the center?
Physics
1 answer:
serg [7]2 years ago
5 0

Answer:

b= 2.14 m

Explanation:

Given that

Weight of the board ,wt = 40 N

Wight of the first children , wt₁=500 N

Weight of the second children ,wt₂ = 350 N

The distance of the 500 N child from center ,a= 1.5 m

lets take distance of the 350 N child from center = b m

Now by taking the moment about the center of the board

We know that moment = Force x Perpendicular distance from the force

wt₁ x a = wt₂ x b

500 x 1.5 = 350 x b

b= 2.14 m

Therefore the distance of the 350 N weight child from the center is 2.14 m.

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Why is the weight of an object more on Earth than on the Moon?
JulijaS [17]
<span>Why is the weight of an object more on Earth than on the Moon? i would say c</span>
8 0
3 years ago
Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. An
Vikentia [17]

Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.

Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.

<h3>What is the relation between the distance in parsecs and the parallax?</h3>
  • Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.
  • Then, the equation connecting parallax and the distance in parsec can be written as,

                                     d=\frac{1}{P}

  • We can say that,

                                    dP=constant.\\thus,\\d_1P_1=d_2P_2

<h3>How to solve the problem?</h3>
  • We have given that,

                                     d_1=2.6 parsecs.\\P_1=0.379arcseconds.\\P_2=0.042 arcseconds.\\d_2=?

  • Thus, we can find the distance in parsecs as,

                                     d_2=\frac{d_1P_1}{P_2} =23.46 parsecs

Thus, we can conclude that, the distance in parsecs will be, 23.46.

Learn more about the relation connecting distance in parsecs and the parallax here: brainly.com/question/28044776

#SPJ4

6 0
1 year ago
Does anyone know how to do this question???<br><br> Force = 7kN <br> Pressure = 1mPa<br> Area = ?
Andreas93 [3]

Answer:

7000 m^2

Explanation:

Pressure=Force/Area

1=7000/Area

1(Area)=7000

Area=7000 m^2

5 0
3 years ago
As the diver jumps, the board bends down. What kind of the energy does the board now have?
Vlada [557]
Hi there!

The energy that is about to or can be released from an object after energy has been transferred to it is called potential energy. In this case, as the diver jumps, potential energy is stored in the board as it bends. The potential energy is then released as kinetic energy when the board springs back up and the diver actually jumps. 

Hope this helps!
8 0
3 years ago
Calculate the electric field at the location of a charge if the electric force is 10 newtons and the charge on the particle is 6
kolezko [41]

I think it may be c, 1.7 v. I work with electricity a lot.


6 0
3 years ago
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