Answer:
1.5 m
Explanation:
Length. L = 12 m
Width, W = 16 m
Area, A = 12 x 16 = 192 m^2
Let the width of pavement be d.
The new length, L' = 12 + 2d
the new width, W' = 16 + 2d
New Area, A' = L' x W' = (12 + 2d)(16 + 2d) = 192 + 56 d + 4d^2
Difference in area = A' - A
285 = 192 + 56 d + 4d^2 - 192
93 = 56 d + 4d^2
4d^2 + 56 d - 93 = 0
\
d = 1.5 m
Thus, the width of the pavement is 1.5 m.
Answer:
The answer to the question is
The correct weight of the former student = 116 lbf
Explanation:
To solve the question, we list out the known variables as follows
Capacity of the scale = 120 lbs
Capacity of the spring dynamometer = 20 lbs
Reading on the scale = 100lb
Reading on the spring dynamometer= 16 lb
at equilibrium, sum of forces = 0
Therefore weight of former student = reaction forces of the scale + the reaction force of the spring dynamometer = 100lb + 16 lb = 116 lb
The correct weight = 116lb weight or 52.62 kg
Converting to weight which is a force = mass * acceleration = 52.62 kg * 9.81 m/s² =
516.2 N = 116 lbf
Answer:
The pushing force and the skier's mass
(A) is correct option.
Explanation:
Given that,
Mass = 64 kg
Weight = 608 N
Velocity = 21 m/s
Forward force = 45 N
We need to calculate the reaction force of the snow pushing on the skier
Using given data,
The reaction force of the snow pushing on the skier is equal to the pushing force and the skier's mass.
Hence, The pushing force and the skier's mass
(A) is correct option.
Answer:
cerro azul
Explanation:
I reverse image searched and it popped up with a name.
