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Marina86 [1]
3 years ago
7

13. A ball is thrown horizontally by a pitcher at 25.0 m/s from shoulder height (2.0m). If the catcher is 20.0 m away, will the

ball reach the catcher before bouncing?​
Physics
1 answer:
Doss [256]3 years ago
7 0

Answer:

The ball will NOT reach the catcher before bouncing

Explanation:

y = (vertical vi)t + (1/2)gt²

2 = 0 + (1/2)(9.8)t²

t = 0.64 s

x = (horizontal vi)t + (1/2)at²

x = (25)(0.64) + 0

x = 16 m

16 m < 20 m

The ball will bounce at 16 m

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a busis moving with the initial velocity 10m/s . after 4 seconds, the velocity becomes 30m/s . find the acceleration produce by
Oksana_A [137]

Answer:

5 m/s²

Explanation:

Use the acceleration formula: a=\frac{v_f-v_i}{t}

  • a = acceleration (m/s²)
  • vf = final velocity (m/s)
  • vi = initial velocity (m/s)
  • t = time (s)

Based on the information given to us by the prompt, we know:

  • vi = 10 m/s
  • vf = 30 m/s
  • t = 4 s

Substitute these values for the variables to calculate the acceleration:

a=\frac{30-10}{4}\\\\a=\frac{20}{4}\\\\a=5

Therefore, the acceleration of the bus is 5 m/s².

7 0
3 years ago
20 kg who is running at a speed of 4.0 m/s jumps onto a stationary sled of mass 5.0 kg on a frozen lake. the speed at which the
Step2247 [10]

Here we can use momentum conservation as there is no external force on sled and child while he jump on sled

by momentum conservation equation

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v{2f}

20*4 + 5*0 = 20*v + 5 *v

since sled and child both moves with same speed so here they both will have same final speed "v"

by solving above equation we will have

25 v = 80

v = 3.2 m/s

So they will move together with speed 3.2 m/s

6 0
3 years ago
A bird is flying directly toward a stationary bird-watcher and emits a frequency of 1420 Hz. The bird-watcher, however, hears a
kogti [31]

Answer:

2.47 %

Explanation:

We are given;

Frequency emitted by source(bird); f_s = 1420 Hz

Frequency heard by observer; f_o = 1456 Hz

From doppler shift frequency, we know that;

f_o = f_s [c/(c - c_s)]

Where c_s is speed of source which is the bird and c is speed of sound.

Thus;

Rearranging the equation, we have;

f_s/f_o = (c - c_s)/c

f_s/f_o = 1 - (c_s/c)

Plugging in the relevant values to get ;

1420/1456 = 1 - (c_s/c)

0.9753 = 1 - (c_s/c)

1 - 0.9753 = (c_s/c)

(c_s/c) = 0.0247

Since we want it expressed im percentage,

Thus, (c_s/c) % = 0.0247 x 100 = 2.47 %

7 0
4 years ago
Greek philosophers such as Demoncritus and Aristotle had ideas about the composition of matter. For example, Demoncritus believe
tino4ka555 [31]

Answer:

D) Dalton's theory had repeated observations which were supported by extensive evidence.

Explanation:

Dalton had a basis for this prediction and theory. He worked extensive on gases before stepping forward with the Dalton's atomic theory.

His scientific conjecture was highly corroborated with a wide array of experimental evidence and many infallible proofs.

  • Science is a logical way of reasoning that follow methodological approaches.
  • It deals with empirical experimental proofs that must have been gathered and the veracity ascertained.
  • Dalton during his time presented the scientific community with a pool of observations balanced with experimental evidences he accumulated with time.  
6 0
4 years ago
A 2.6 kg mass attached to a light string rotates on a horizontal,
Ainat [17]

The maximum speed the mass can have before it breaks is 2.27 m/s.

The given parameters:

  • <em>maximum mass the string can support before breaking, m = 17.9 kg</em>
  • <em>radius of the circle, r = 0.525 m</em>

The maximum speed the mass can have before it breaks is calculated as follows;

T = ma_c\\\\Mg = \frac{Mv^2}{r} \\\\v^2 = rg\\\\v = \sqrt{rg} \\\\v_{max} = \sqrt{0.525 \times 9.8} \\\\v_{max} = 2.27 \ m/s

Thus, the maximum speed the mass can have before it breaks is 2.27 m/s.

Learn more about maximum speed of horizontal circle here:brainly.com/question/21971127

8 0
3 years ago
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