The working equation for this one is:
E = F/Q, where E is the strength of the electric field, F is the electric force and Q is the charge. Substituting the corresponding values, the strength of the electric field is equal to
E = -30 nN/-3 nC
E = 10 nN/nC
Answer:
0.888 ohm
Explanation:
We have given that the battery has an emf of 12 volt that E =12 volt
Terminal voltage V =18.4 volt
Current through the battery is =7.20 A
We have top find the internal resistance of the battery
Now according to Kirchhoff's law V=E+IR
So 
So the value of internal resistance of battery is 0.888 ohm
These cases are rare, but what happens is something called an occluded front. There are so many things that could be talked about and results aren't typically constant, so I recommend you look up what an occluded front is. Its basically when a cold front catches up to a warm front and forces even more warm air up, causing high amounts of precipitation.
Without knowing anything about their magnitudes or directions, the only thing you can always say about thier combination is that it's the "net force" on the object.
There will be four unpaired electrons
The metal complex is [FeX₆]³⁻
X being the halogen ligand
X = F, CL, Br, and I
The oxidation of metal state is +3
The ground state configuration is
₂₆Fe =Is² 2s²2p⁶ 3s² 3p⁶ 3d⁶ 4s²
Metal, Fe(III) ion electron configures
₂₆Fe³⁺ = Is2 2s² 2p⁶ 3s² 3p⁶ 3d⁵
