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ValentinkaMS [17]
3 years ago
7

What has mass and takes up space? A. matter B. weight C. volume D. space

Chemistry
2 answers:
spayn [35]3 years ago
7 0

Answer:

Matter is anything that has mass and takes up space.

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u></h3>
OLEGan [10]3 years ago
4 0
Answer: A. Matter

Explanation: anything that has matter has a definite shape and volume.
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Determine the length of the object shown <br>A. 97.8 mm<br>B. 97.80 mm<br>C. 97 mm<br>D. 98 mm​
jeka94

Answer:

A. 97.8 mm  

Explanation:

There are 10 divisions between 9 cm (90 mm) and the end of the ruler (10 cm or 100 mm).

Each division equals 1 mm.

Each 5 mm mark has a longer tick, and the dashed red line is between the 97 mm and 98 mm marks.

You would normally estimate to the nearest tenth of a division. An estimate of 0.8 mm is reasonable.

The length of the object is 97.0 mm + 0.8 mm = 97.8 mm.

B is wrong. You can't possibly estimate to the nearest hundredth of a division.  

C is wrong. The dashed red line slightly before the 98 mm mark.

D is wrong. If the dashed red line were exactly on the 98 mm mark, you would record the measurement as 98.0 mm. This indicates that you measured the object to zero tenths on either side of the mark.

 

6 0
3 years ago
Calculate the number of C, H, and O atoms in 1.50 g of glucose, a sugar
DIA [1.3K]
Chemical formula of the glucose: C₆H₁₂O₆

We calculate the molar mass:
atomic mass (C)=12 u
atomic mass (H)=1 u
atomic mass (O)=16 u

atomic weight (C₆H₁₂O₆)=6(12 u)+12(1u)+6(16 u)=72 u+12u+96 u=180 u.
Therefore : 1 mol of glucose will be 180 g
The molar mass would be: 180 g/ mol


2) we calculate the number of moles of 1.5 g.
180 g---------------------1 mol
1.5 g----------------------  x

x=(1.5 g * 1 mol) / 180 g≈8.33*10⁻³ moles

we knows that:
1 mol = 6.022 * 10²³ particles (atoms or molecules)

3)We calculate the number of molecules:

Therefore:
1 mol-----------------------6.022*10²³ molecules of glucose
8.33*10⁻³ moles--------        x

x=(8.33*10⁻³ moles * 6.022*10²³ molecules)/1 mol≈5.0183*10²¹ molecules.

4)We calculate the number of C, H and O atoms:
A molecule of glucose have 6 atoms of C, 12 atoms of H, and 6 atoms of O,
number of atoms of C=(6 atoms/1 molecule)(5.0183*10²¹molecules)≈
3.011*10²²

number of atoms of H=(12 atoms/1 molecule)(5.0183*10²¹ molecules)≈
6.022*10²² .

number of atoms of O=(6 atoms/1 molecule)(5.0183*10²¹ molecules)≈
3.011*10²²

Answer: we have 3.011*10²² atoms of C, 6.022*10²² atoms of H, and 3.011*10²² atoms of O.
4 0
3 years ago
Help pleas I dont understand
Temka [501]
The *independent* variable is the one that you always can control. However, the dependent variables are not since they **depend** on another.
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3 years ago
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Which of the following is a transuranium element?<br> Ra<br> Am<br> Tc<br> Pa
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Am - it has an atomic number of 95 which is greater than 92.

Transuranium elements are elements with atomic levels greater than 92
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Biotic - animals anything tht is living abiotic anything tht is non-living

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