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jarptica [38.1K]
3 years ago
8

On your first day working in a laboratory, you are told to make up 1 Liter of a 0.5 Molar Tris solution with a pH of 7.4. You me

asure out the appropriate amount of Tris base and dissolve it in water. You then measure the pH and find out that it has an initial pH of 11. You add some concentrated HCl, and the pH begins to drop. However, as you approach the target pH, you find that you need to add large amounts of HCl to lower the pH even a small amount. If the molecular weight of Tris base is 121.14, how many grams did you use
Chemistry
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

60.57g of TRIS did you use

Explanation:

The concentration of the Tris solution buffer is 0.5 molar (That is, 0.5 moles per liter). As you need to make 1L, you need to have in the solution <em>0.5 moles of TRIS.</em>

<em />

To convert these moles of TRIS to grams you need to use the molecular weight of TRIS base (121.14g/mol), thus:

0.5 moles TRIS * (121.14g / mol) =

<h3>60.57g of TRIS did you use</h3>
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g Determine the empirical formula for a compound that contains C, H and O. It contains 40.92% C, 4.58% H, and 54.50% O by mass.
Lady bird [3.3K]

Answer:

The empirical formula for the compound is C3H4O3

Explanation:

The following data were obtained from the question:

Carbon (C) = 40.92%

Hydrogen (H) = 4.58%

Oxygen (O) = 54.50%

The empirical formula for the compound can be obtained as follow:

C = 40.92%

H = 4.58%

O = 54.50%

Divide by their molar mass

C = 40.92/12 = 3.41

H = 4.58/1 = 4.58

O = 54.50/16 = 3.41

Divide by the smallest i.e 3.41

C = 3.41/3.41 = 1

H = 4.58/3.41 = 1.3

O = 3.41/3.41 = 1

Multiply through by 3 to express in whole number

C = 1 x 3 = 3

H = 1.3 x 3 = 4

O = 1 x 3 = 3

The empirical formula for the compound is C3H4O3

6 0
3 years ago
What is the mass of a steel cylinder that has a density of 75.0 g/mL and a volume of 12 mL?
siniylev [52]
<span>
hey there!:

density = 75.0 g/mL

Volume = 12 mL

mass = ?

Therefore:

D = m / V

75.0 =m / 12

m = 75.0 * 12

m = 900 g

Answer B

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5 0
3 years ago
Read 2 more answers
Solution A: pH of 10
serious [3.7K]

Answer:

I think it’s C,B,A

Explanation:

5 0
2 years ago
A 3.00-l flask is filled with gaseous ammonia, nh3. the gas pressure measured at 15.0 ∘c is 2.15 atm . assuming ideal gas behavi
Leokris [45]
We can find the mass of ammonia using the ideal gas law equation,
PV = nRT
where 
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V - volume - 3.00 x 10⁻³ m³
n - number of moles 
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in kelvin - 15.0 °C + 273 = 288 K
substituting these values in the equation 
2.18 x 10⁵ Pa x 3.00 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 288 K
n = 0.273 mol 
number of moles of NH₃ is 0.273 mol 
molar mass of NH₃ - 17.0 g/mol 
mass pf ammonia present - 0.273 mol x 17.0 g/mol = 4.64 g
mass of NH₃ present is 4.64 g
8 0
3 years ago
2 CO + O2= CO2<br><br>balance or not?​
suter [353]

Answer:

No, The equation is not balanced

The correct ans is

2CO+O2=2CO2

7 0
2 years ago
Read 2 more answers
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