The molarity of a solution is 0.909 M.
m(CaCl₂) = 82 g; mass of calcium chloride
M(CaCl₂) = 111 g/mol; molar mass of calcium chloride
n(CaCl₂) = m(CaCl₂) ÷ M(CaCl₂)
n(CaCl₂) = 82 g ÷ 111 g/mol
n(CaCl₂) = 0.74 mol; amount of calcium chloride
V(CaCl₂) = 812 mL = 0.812 L; volume of calcium chloride
c(CaCl₂) = n(CaCl₂) ÷ V(CaCl₂)
c(CaCl₂) = 0.74 mol ÷ 0.812 L
c(CaCl₂) = 0.909 mol/L = 0.909 M; molarity of calcium chloride
Calcium chloride is a inorganic salt with ionic bonds between calcium and chlorine. It is a colorless crystalline solid at room temperature, highly soluble in water.
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It would be C
2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj
Answer:
0.05
moles
Explanation:
In a mole of any substance, there exist
6.02⋅1023
units of that substance.
So here, we got:
3.01⋅1022Mg atoms⋅1mol6.02⋅1023M gatoms=0.05mol
