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3 years ago

A compound is found to contain 7.523% phosphorus and 92.48% iodine by weight. what is the empirical formula for this compound?

Chemistry

2 answers:

BaLLatris [955]3 years ago

7 0

Answer:

PI₃

Explanation:

The empirical formula is found using the molar ratio between phosphorus and iodine.

The phosphorus composes 7.523% by weight of the substance, or 7.523g of phosphorus per gram of the substance. The moles of phosphorus per gram of substance is calculated using the atomic weight of phosphorus (30.97 g/mol):

(7.523g P) / (1 g substance) x (mol/30.97g P) = (0.2429 mol P) / (1 g substance)

Similarly, the moles of iodine (atomic weight 126.90 g/mol) per gram of substance is found:

(92.48 g I) / (1 g substance) x (mol/126.90 g I) = (0.7288 mol I) / (1 g substance)

The molar ratio between P and I is found by dividing the two values calculated above:

(0.7288 mol I) / (1 g substance) ÷ (0.2429 mol P) / (1 g substance) = (3.00 mol I) / (mol P)

Thus, the ratio of iodine to phosphorus is 3:1, so the empirical formula (the simplest formula) is PI₃

RUDIKE [14]3 years ago

5 0

The answer is PI3
Ratio of 1:3

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Answer:

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Explanation:

Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.

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$\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}\\\frac{P_{1}}{T_{1}} =\frac{P_{2}}{0.5T_{1}}\\\\P_{2}=0.5P_{1}$

Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.

n₂ = 0.5 n₁.

P₁ in terms of the ideal gas equation is:

$P_{1}=\frac{n_{1}.R.T_{1}}{V_{1}}$

P₂ in terms of the ideal gas equation is:

$P_{2}=\frac{n_{2}.R.T_{1}}{V_{1}}=\frac{0.5n_{1}.R.T_{1}}{V_{1}}=0.5P_{1}$

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3 years ago

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Answer:

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Binary compounds of silver chlorine:

AgCl

Binary compounds of calcium and oxygen:

CaO

Binary compounds of aluminium and iodine:

AlI₃

Binary compounds of barium and nitrogen:

Ba₃ N₂

Binary compounds of sodium and selenium:

Na₂Se

Explanation:

Binary compounds:

The compounds which are made up of the atoms of only two elements are called binary compounds.

For example:

The following compounds are binary:

HCl

H₂O

NH₃

HCl is binary because it is composed of only hydrogen and chlorine. Ammonia is also binary compound because it is made up of only two elements nitrogen and hydrogen.

water is also binary because it is also made up of only two elements hydrogen and oxygen.

Binary compounds of potassium and sulfur:

K₂S

The oxidation state of potassium is +1 and sulfur is -2 so two atoms of potassium will combine with one atom of sulfur.

Binary compounds of silver chlorine:

AgCl

The oxidation state of silver is +1 and chlorine is -1. Both combine to form silver chloride.

Binary compounds of calcium and oxygen:

CaO

calcium oxide is formed by calcium and oxygen. The oxidation state of calcium is +2 and oxygen is -2.

Binary compounds of aluminium and iodine:

AlI₃

The oxidation state of aluminium is +3 and iodine is -1 so three atoms of iodine will combine with one atom of aluminium.

Binary compounds of barium and nitrogen:

Ba₃ N₂

Barium nitride is formed by barium and nitrogen. The oxidation state of nitrogen is -3 and barium is +2.

Binary compounds of sodium and selenium:

Na₂Se

The oxidation state of selenium is -2 ans sodium is +1 so two atoms of sodium will combine with one atom of selenium.

5 0

3 years ago

In naming the compound PCl5, the prefix used with the second element is ____________________.

Oksanka [162]

Answer:

$\boxed {\boxed {\sf Hepta}}$

Explanation:

We are given the formula:

$PCl_5$

This is a molecular formula, because it contains nonmetals.

1. Name the first element

The first element is phosphorous (P). Since this is the first element and there is only one, we don't need a prefix.

Phosphorous

2. Second element

The second element is chlorine (Cl). It has a subscript of 5, so we must add the prefix of hepta-.

Phosphorous heptachlorine

Add the ending of -ide.

Phosphorous heptachloride

The prefix used for the second element is hepta. The compound name is phosphorous heptachloride.

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