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Alinara [238K]
3 years ago
8

How should pure water be classified with respect to its electrical conductivity properties?

Chemistry
1 answer:
vovikov84 [41]3 years ago
6 0
Pure water would be classified as non-conductor since it does not allow the flow of current into the solution. It does not contains any ions or free electrons so it cannot allow the flow of current into the system. It can allow current only when any impurities is present like salts.
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If a combination reaction takes place between rubidium and bromine, the chemical formula for the product is
lesya [120]
The chemical formula for the product is RbBr.
7 0
3 years ago
Which is a fossil fuel?<br> O A. Coal<br> O B. Biomass<br> O C. Geothermal<br> O D. Nuclear
creativ13 [48]

Answer:

coal

Explanation:

fossil fuels are formed by natural process.

3 0
3 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

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5 0
2 years ago
6. The modern view of the atom has come a long way from that of a solid, indestructible sphere
Fynjy0 [20]
It is a true statement
4 0
3 years ago
Assuming all volume measurements are made at the same temperature and pressure, how many liters of oxygen gas would it take to r
EleoNora [17]
2H2 (g) + O2 (g) -->2H2 O(g)
mole ratio of H2:O2=2:1
7.25/2=3.625
3 0
3 years ago
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