Answer: touch the pan to the burner
Explanation:
There are three modes of heat transfer:
conduction, convection and radiation.
For conduction, the heat transfers from a hot object to a cold object when the two are in contact.
For convection there is bulk motion of fluid occurs which transfers the heat.
For heat transfer by radiation, medium is not required.
Thus, to demonstrate conduction between pan and burner, the pan must touch the burner.
Answer:
the sp³ orbital, is a very directional orbital that forms the bonds called covalent. the material is an electrical Insulator. hardness of the material comes from the energy needed to break the covalent bonds (sp³)
Explanation:
Carbon has several structures, for its different ways of bonding, in all these the orbital s is excited and mixed with the orbitals p, creating hybrid orbitals sp³, sp² and sp, there are some π orbitals around the latter.
Each type of hybrid orbital is linked differently, the sp³ orbital, is a very directional orbital that forms the bonds called covalent, where when it binds to another atom they share an electron, therefore the 4 sp³ orbitals form a stable molecule with full orbitals (8 electrons).
As the electrons are in the direction of the links, they cannot be easily moved, so the material is an electrical Insulator.
The hardness of the material comes from the energy needed to break the covalent bonds (sp³), there are only a few directions in which the links can be separated
Answer:0.210 ft/min
Explanation:
Given
Length of trough
width of base
height of triangle
From Similar triangles property
volume of water in time t
differentiating
at
From an energy balance, we can use this formula to solve for the angular speed of the chimney
ω^2 = 3g / h sin θ
Substituting the given values:
ω^2 = 3 (9.81) / 53.2 sin 34.1
ω^2 = 0.987 /s
The formula for radial acceleration is:
a = rω^2
So,
a = 53.2 (0.987) = 52.494 /s^2
The linear velocity is:
v^2 = ar
v^2 = 52.949 (53.2) = 2816.887
The tangential acceleration is:
a = r v^2
a = 53.2 (2816.887)
a = 149858.378 m/s^2
If the tangential acceleration is equal to g:
g = r^2 3g / sin θ
Solving for θ
θ = 67°